 GNU编译器的公式计算问题，怎么使用C语言的程序的设计的过程的编写的代码去解决的

Problem Description
The GNU Compiler Collection (usually shortened to GCC) is a compiler system produced by the GNU Project supporting various programming languages. But it doesn’t contains the math operator “!”.
In mathematics the symbol represents the factorial operation. The expression n! means "the product of the integers from 1 to n". For example, 4! (read four factorial) is 4 × 3 × 2 × 1 = 24. (0! is defined as 1, which is a neutral element in multiplication, not multiplied by anything.)
We want you to help us with this formation: (0! + 1! + 2! + 3! + 4! + ... + n!)%mInput
The first line consists of an integer T, indicating the number of test cases.
Each test on a single consists of two integer n and m.Output
Output the answer of (0! + 1! + 2! + 3! + 4! + ... + n!)%m.Constrains
0 < T <= 20
0 <= n < 10^100 (without leading zero)
0 < m < 1000000Sample Input
1
10 861017Sample Output
593846
Sum 求和问题_course
20200203Description Consider the natural numbers from 1 to N. By associating to each number a sign (+ or ) and calculating the value of this expression we obtain a sum S. The problem is to determine for a given sum S the minimum number N for which we can obtain S by associating signs for all numbers between 1 to N. For a given S, find out the minimum value N in order to obtain S according to the conditions of the problem. Input The only line contains in the first line a positive integer S (0< S <= 100000) which represents the sum to be obtained. Output The output will contain the minimum number N for which the sum S can be obtained. Sample Input 12 Sample Output 7
Go , SuSu 的编写_course
20200107Problem Description When SuSu and his friends visited GanQuan village , something dangerous happened on them . They were trapped in a mysterious cave , what was worse ,there was a terrible monster lived in the cave , so they had to escape from the cave as quickly as possible . But little monsters were also in the cave, as a result ,when SuSu was seen by the little monsters ,they would notice their boss to catch SuSu back. Little monsters' visual field is showed in figure A. The grid colored red represents where the monster stands, the arrow represents which direction the monster walk to ,and the grids colored blue and red represents where the very monster can see at this moment. The monsters often walks in a straight line, and when they faces a wall or the boundary of the maze in front of him, they will cost 1 seconds to turn back, and then walk back along the straight line, until reach a wall again. If SuSu was seen by the monsters ,it's impossible for them to escape from the cave . SuSu needs your help , please tell him the minimum time he needs to walk from the start point to the exit of the cave , be careful not to be seen by the monsters. Every seconds SuSu can move upward downward leftward and rightward , and can also make no movement. Figure A Input The first line of input gives the number of cases, T (at most 90). the first line of each case has four numbers n,m. (2<=n,m<=50) then n lines with m characters describe the maze 'A' represents the init position of SuSu. 'B' represents the exit position of the cave. '.' represents the grids can be walked on. '*' represents the wall which can not be stepped on. Then follows a number k (at most 50). Next k lines with three integers x , y , d (1 <= x <= n,1 <= y <= m,1 <= d <= 4).represents a monster walking to d direction is in (x,y) positon (the topleft grid is (1,1) ) at 0 seconds . The monster walks up when d == 1. walk down when d == 2.walk left when d == 3.walk right when d == 4. Output If SuSu can get to the exit in 1000 seconds ,output the minimum time he need. print "胜败兵家事不期 卷土重来是大侠" otherwise. Following the case number (start with 1). Sample Input 1 3 4 *.*. .A.B ***. 1 3 4 1 Sample Output Case 1: 2
Keywords Search 关键字的查找_course
20200105Problem Description In the modern time, Search engine came into the life of everybody like Google, Baidu, etc. Wiskey also wants to bring this feature to his image retrieval system. Every image have a long description, when users type some keywords to find the image, the system will match the keywords with description of image and show the image which the most keywords be matched. To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords will be match. Input First line will contain one integer means how many cases will follow by. Each case will contain two integers N means the number of keywords and N keywords follow. (N <= 10000) Each keyword will only contains characters 'a''z', and the length will be not longer than 50. The last line is the description, and the length will be not longer than 1000000. Output Print how many keywords are contained in the description. Sample Input 1 5 she he say shr her yasherhs Sample Output 3
统计一个给定字符串中指定的字符出现的次数_course
20191227Problem Description 统计一个给定字符串中指定的字符出现的次数 Input 测试输入包含若干测试用例，每个测试用例包含2行，第1行为一个长度不超过5的字符串，第2行为一个长度不超过80的字符串。注意这里的字符串包含空格，即空格也可能是要求被统计的字符之一。当读到'#'时输入结束，相应的结果不要输出。 Output 对每个测试用例，统计第1行中字符串的每个字符在第2行字符串中出现的次数，按如下格式输出： c0 n0 c1 n1 c2 n2 ... 其中ci是第1行中第i个字符，ni是ci出现的次数。 Sample Input I THIS IS A TEST i ng this is a long test string # Sample Output I 2 i 3 5 n 2 g 2
输出多项式的系数使得给定的方程成立，怎么用C语言的程序的设计的代码编写的思想方法来实现的_course
20190613Problem Description Li Zhixiang have already been in “Friendship” oceangoing freighter for three months. The excitement has gradually disappeared. He stands on the board, holding the railing and watching the dazzling ocean in the sun silently. Day after day, the same scenery is monotonous and tasteless, even the merry seagulls following the freighter cannot arouse his interest. Hearing the footsteps behind, he turns back to see the old captain is coming towards him. The captain has understood his idea, however, he starts a new topic with the young man. “Do you know how far our voyage is?” The captain asks. Li Zhixiang feels ashamed because he can not answer. Then the captain says with a smile, “5050 miles. Do you still remember the story of 5050?” This time the young man really blushes. The old captain continues saying:” You definitely know the story of 5050. When the German mathematician, “the prince of mathematicians”, Gauss was 10 years old …” Young man remembers this story and goes on to tell, “ When Gauss was 10 years old, he could add a list of integers from 1 to 100 in a few seconds, which shocked the teachers.” The old captain adds, “Gauss has many other stories like this. When he entered the university at the age of 17, he was able to construct heptadecagon by compass and straightedge. His university teachers were also impressed by his ability. Not only could college graduate students fail to do it, but also they felt hard to understand Gauss’s constructing process.” At this time, vicecaptain greets the old captain. The old captain says to Li Zhixiang: “Come over to my office tonight, let’s continue the conversation.” It is still calm and tranquil in the evening. The freighter travels smoothly on the sea in the silver moonlight. The captain tells the young man the following words. Among the mathematicians through the ages, there are three greatest mathematicians: Archimedes, Newton and Gauss. Most of Gauss’s mathematical achievements are difficult to understand. Nevertheless, there are some comparatively easy. For instance, when it comes to solving multivariate system of linear equations, there is a solution called “Gauss Elimination”. In the navigation business, many problems can be solved by “Gauss elimination”. If you are interested in it, I will show you a simple question. Try it.” Input There are several test cases. In the first line of each case, a number n indicates that there are n equations. The following n lines, each line has n+1 numbers, ai1,ai2,ai3…..ain, bi(1<= i <=n), these numbers indicate the coefficients of systems of the equations. ai1*x1+ai2*x2+......ain*xn=bi. Input is terminated by the end of file. Output For each given systems of equations, if there are solutions, output n solutions in the order of appearance in the equations（n<=100）, each solution number is in one line. If solution is not integer, show it in fraction. If no solution, output “No solution.” Leave a blank line after each case. Sample Input 2 1000000000000000000000000 1000000000000000000000000 1000000000000000000000000 1000000000000000000000000 1000000000000000000000000 0 1 0 4 Sample Output 1/2 1/2 No solution.
Range 区间的问题_course
20200416Problem Description Some automobiles display the estimated driving range, that is, the distance you can expect to drive it (without adding fuel) before running out of fuel. Here is how it works: periodically, the vehicle's computer records the odometer reading and the weight of fuel in the fuel tank. From this data, the fuel consumption over a certain distance can be computed. From the fuel consumption and the most recent measurement of fuel tank contents (which we assume is current for all practical purposes), the range can be calculated. Intervals over which the quantity of fuel increased (fuel was added to the tank) will not be used in the computations. For example, in the first problem instance of the sample input, the interval where the fuel weight increased from 29.9 kilograms to 34.2 kilograms will not be used. In this example, 16.3 kilograms of fuel were consumed over a distance of 228.6 kilometers. Therefore, the most recently measured fuel contents of 31.2 kilograms will enable you to drive another 438 kilometers (rounded to the nearest integer). The input will always contain at least one interval (two consecutive lines of input) where no fuel was added to the tank. Input The input contains data for a number of problem instances. Each problem instance consists of three or more (odometer reading, fuel weight) pairs, one pair per line. Distances are measured in kilometers and fuel weight in kilograms. All input numbers will be given to one decimal place. The end of each problem instance will be signaled by a (0.0, 0.0) pair. The last problem instance will be followed by a (1.0, 1.0) pair. Output For each problem instance, print the range, rounded to the nearest integer. Sample Input 18400.5 43.2 18440.4 40.4 18482.7 37.0 18540.2 33.1 18585.3 29.9 18620.8 34.2 18664.6 31.2 0.0 0.0 18400.5 43.2 18440.4 40.4 18482.7 37.0 18540.2 33.1 18585.3 29.9 0.0 0.0 1.0 1.0 Sample Output 438 415
C 语言来实现进制转换_course
20190819Problem Description 输入一个十进制数N，将它转换成R进制数输出。 Input 输入数据包含多个测试实例，每个测试实例包含两个整数N(32位整数)和R（2<=R<=16, R<>10）。 Output 为每个测试实例输出转换后的数，每个输出占一行。如果R大于10，则对应的数字规则参考16进制（比如，10用A表示，等等）。 Sample Input 7 2 23 12 4 3 Sample Output 111 1B 11
首字母变大写 应该如何实现呢_course
20200526Problem Description 输入一个英文句子，将每个单词的第一个字母改成大写字母。 Input 输入数据包含多个测试实例，每个测试实例是一个长度不超过100的英文句子，占一行。 Output 请输出按照要求改写后的英文句子。 Sample Input i like acm i want to get an accepted Sample Output I Like Acm I Want To Get An Accepted
从Golang的stdin读取_course
20150315<div class="posttext" itemprop="text"> <p>I'm trying to read from Stdin in Golang as I'm trying to implement a driver for Erlang. I have the following code:</p> <pre><code>package main import ( "fmt" "os" "bufio" "time" ) func main() { go func() { stdout := bufio.NewWriter(os.Stdin) p := []byte{121,100,125,' '} stdout.Write(p) }() stdin := bufio.NewReader(os.Stdin) values := make([]byte,4,4) for{ fmt.Println("b") if read_exact(stdin) > 0 { stdin.Read(values) fmt.Println("a") give_func_write(values) }else{ continue } } } func read_exact(r *bufio.Reader) int { bits := make([]byte,3,3) a,_ := r.Read(bits) if a > 0 { r.Reset(r) return 1 } return 1 } func give_func_write(a []byte) bool { fmt.Println("Yahu") return true } </code></pre> <p>However it seems that the <code>give_func_write</code> is never reached. I tried to start a goroutine to write to standard input after 2 seconds to test this.</p> <p>What am I missing here? Also the line <code>r.Reset(r)</code>. Is this valid in go? What I tried to achieve is simply restart the reading from the beginning of the file. Is there a better way?</p> <p><strong>EDIT</strong></p> <p>After having played around I was able to find that the code is stuck at <code>a,_ := r.Read(bits)</code> in the <code>read_exact</code> function</p> </div>
等差数列的问题，采用C 语言如何才能进行求解呢？？_course
20190107Problem Description A sequence b1,b2,⋯,bn are called (d1,d2)arithmetic sequence if and only if there exist i(1≤i≤n) such that for every j(1≤j<i),bj+1=bj+d1 and for every j(i≤j<n),bj+1=bj+d2. Teacher Mai has a sequence a1,a2,⋯,an. He wants to know how many intervals [l,r](1≤l≤r≤n) there are that al,al+1,⋯,ar are (d1,d2)arithmetic sequence. Input There are multiple test cases. For each test case, the first line contains three numbers n,d1,d2(1≤n≤105,d1,d2≤1000), the next line contains n integers a1,a2,⋯,an(ai≤109). Output For each test case, print the answer. Sample Input 5 2 2 0 2 0 2 0 5 2 3 2 3 3 3 3 Sample Output 12 5
怎么运用 C 语言的程序，Cylinder_course
20190810Problem Description Using a sheet of paper and scissors, you can cut out two faces to form a cylinder in the following way: 1. Cut the paper horizontally (parallel to the shorter side) to get two rectangular parts. 2. From the first part, cut out a circle of maximum radius. The circle will form the bottom of the cylinder. 3. Roll the second part up in such a way that it has a perimeter of equal length with the circle's circumference, and attach one end of the roll to the circle. Note that the roll may have some overlapping parts in order to get the required length of the perimeter. Given the dimensions of the sheet of paper, can you calculate the biggest possible volume of a cylinder which can be constructed using the procedure described above? Input The input consists of several test cases. Each test case consists of two numbers w and h (1 ≤ w ≤ h ≤ 100), which indicate the width and height of the sheet of paper. The last test case is followed by a line containing two zeros. Output For each test case, print one line with the biggest possible volume of the cylinder. Round this number to 3 places after the decimal point. Sample Input 10 10 10 50 10 30 0 0 Sample Output 54.247 785.398 412.095
偶数求和 是怎么实现的呢_course
20200526偶数求和 Problem Description 有一个长度为n(n<=100)的数列，该数列定义为从2开始的递增有序偶数，现在要求你按照顺序每m个数求出一个平均值，如果最后不足m个，则以实际数量求平均值。编程输出该平均值序列。 Input 输入数据有多组，每组占一行，包含两个正整数n和m，n和m的含义如上所述。 Output 对于每组输入数据，输出一个平均值序列，每组输出占一行。 Sample Input 3 2 4 2 Sample Output 3 6 3 7
SCV集合的查询和数组操作的问题，采用C技术语言_course
20190123Problem Description StarCraft 2 (SC2) is a famous game. More and more people fall in love with this game. As a crazy fan of SC2, Ahua (flower fairy) play it day and night. Recently, he found that the most important part of being a top player of SC2 is economic development, which means you should get as much mine as possible by training SCVs (space construction vehicle) to collect mine. Train a SCV at ith second costs Ci units of mine. After training, this SCV can collect Di units of mine each second. Training a SCV needs one second of time. Based on that, he composes a formula to evaluate the development in a time span from xth second to yth second. Assume at xth second, Ahua has no SCV and mine. He trains one SCV at each second during xth second and yth second (the mount of mine can be negative, so that he always can train SCV). Each SCV will collect some amount of mines for Ahua in each second after it was trained. At ith second Ahua has Mi units of mine in total. The development value is defined as sum(Mi) (x ≤ i ≤ y). Now he asks you to help him calculate the development value. To make it more interesting, Ahua can apply following operations: Cost x y z: the cost of training a SCV between xth second to yth second will increase by z units of mine. i.e. Ci for x ≤ i ≤ y will increase by z. Collect x y z: each SCV trained between xth second and yth second can collect z more mines every second after it has been trained. i.e. Di for x ≤ i ≤ y will increase by z. Query x y: output the development value between xth second and yth second. Input First line of the input is a single integer T (T ≤ 10), indicates there are T test cases. For each test case, the first line is an integer N (1 ≤ N ≤ 100000), means the maximum time you should deal with. Following N lines, each contain two integers Ci and Di (0 ≤ Ci, Di ≤ 100000), the cost and collect speed of SCV training in ith second initially as described above. The next line is an integer Q (1 ≤ Q ≤ 10000), the number of operations you should deal with. Then Q lines followed, each line will be “Cost x y z”, "Collect x y z” or “Query x y”. 1 ≤ x ≤ y ≤ N, 0 ≤ z ≤ 100000 Output For each test case, first output “Case k: “ in a single line, k is the number of the test case, from 1 to T. Then for each "Q x y", you should output a single line contains the answer mod 20110911. Sample Input 1 5 1 3 2 3 3 1 2 2 3 3 5 Query 1 3 Cost 2 2 1 Query 1 3 Collect 1 1 5 Query 1 3 Sample Output Case 1: 2 0 15
绝对值距离的计算、寻路问题，怎么采用C程序的语言代码的编写的方式去计算结果？_course
20190526Problem Description We'll consider an interesting geometric problem here. Given a number of circles with varying radius on the plane, and define the Pvalue of a point (x, y) on the plane as the number of circles covering this point. Here, by "covering", we mean that the point is either strictly within the circle, or on the boundary of the circle. Given the starting position (Sx, Sy), and the destination position (Tx, Ty), please find a path between the two points, such that every point of the path is on the boundary of one or more circles, and the absolute difference between the maximum Pvalue and the minimum Pvalue among all points on the path is minimized. Can you find the minimum absolute value with the help of your computer? Input There are multiple test cases in the input file. Each test case starts with one integer N (1 <= N <= 150), the number of circles, followed by four real numbers, Sx, Sy, Tx, Ty, representing the xcoordinate and ycoordinate of the starting position and the destination. Each of the following N lines consists of three real numbers X, Y and R (R >= 1), indicating that there is a circle at position (X, Y) with radius R. There is a blank line after each test case. Input ends with EndofFile. Note: It is guaranteed that the input data is always legal, i.e. both the starting position and the destination are on the boundary of one or more circles, no two circles will be at the same position, every real number in the input file has at most three digits after the decimal point, and the absolute value of any real number does not exceed 10000. Output For each test case, output one integer on one separate line as requested. If there is no way to reach the destination, output 1 instead. Sample Input 2 1.000 0.000 1.000 0.000 0.000 0.000 1.000 1.000 0.000 1.000 2 1.000 0.000 5.000 0.000 1.000 1.000 1.000 4.000 0.000 1.000 Sample Output Case 1: 1 Case 2: 1
数据结构字符串数组的一个运用，怎么采用C程序编写的语言的算法实现的程序？_course
20190502Problem Description Name PK is a funny game on the Internet. The game will calculate character's property based on its name. Now we're simulating a simple Name PK game. Each character has 3 parameters: HP, STR and SPD (HP for health point, STR for strength and SPD for attacking speed). For a name string of length N, Ci is ASCII code (decimal) of the ith char. PK rule: 1. Timer begins to increase from 1. When it is a multiple of (20SPD), the corresponding character A has that SPD attack once, the opposite lose STR(A's) HP. 2. When any side has a HP ≤ 0, the PK is over. Input The input consists of several test cases. The first line of input consists of an integer T, indicating the number of test cases. Each test case is on a separate line, and it consists two strings separated by a whitespace, indicating the name of the characters. Technical Specification 1. Names contain only English letters. 2. The length of each character's name is more than 1 and no more than 20. 3. T ≤ 1000. Output For each test case, output a line consisting of the result of the first character: "win", "lose" or "tie". Sample Input 3 Sylvia xay Ivan Stacy Boyd Greg Sample Output lose win lose
Coverage 是怎么实现的_course
20200416Problem Description A cell phone user is travelling along a line segment with end points having integer coordinates. In order for the user to have cell phone coverage, it must be within the transmission radius of some transmission tower. As the user travels along the path, cell phone coverage may be gained (or lost) as the user moves inside the radius of some tower (or outside of the radii of all towers). Given the location of up to 100 towers and their transmission radii, you are to compute the percentage of cell phone coverage the user has along the specified path. The (x,y) coordinates are integers between 100 and 100, inclusive, and the tower radii are integers between 1 and 100, inclusive. Input Your program will be given a sequence of configurations, one per line, of the form: N C0X C0Y C1X C1Y T1X T1Y T1R T2X T2Y T2R ... Here, N is the number of towers, (C0X,C0Y) is the start of path of the cell phone user, (C1X,C1Y) is the end of the path, (TkX,TkY) is the position of the kth tower, and TkR is its transmission radius. The start and end points of the paths are distinct. The last problem is terminated by the line 0 Output For each configuration, output one line containing the percentage of coverage the cell phone has, rounded to two decimal places. Sample Input 3 0 0 100 0 0 0 10 5 0 10 15 0 10 1 0 0 100 0 40 10 50 0 Sample Output 25.00 88.99
用C语言进行，超大数字的计算问题_course
20190809Description In how many ways can you tile a 2xn rectangle by 2x1 or 2x2 tiles? Here is a sample tiling of a 2x17 rectangle. Input Input is a sequence of lines, each line containing an integer number 0 <= n <= 250. Output For each line of input, output one integer number in a separate line giving the number of possible tilings of a 2xn rectangle. Sample Input 2 8 12 100 200 Sample Output 3 171 2731 845100400152152934331135470251 1071292029505993517027974728227441735014801995855195223534251
水仙花数 C语言_course
20191206Problem Description 春天是鲜花的季节，水仙花就是其中最迷人的代表，数学上有个水仙花数，他是这样定义的： “水仙花数”是指一个三位数，它的各位数字的立方和等于其本身，比如：153=1^3+5^3+3^3。 现在要求输出所有在m和n范围内的水仙花数。 Input 输入数据有多组，每组占一行，包括两个整数m和n（100<=m<=n<=999）。 Output 对于每个测试实例，要求输出所有在给定范围内的水仙花数，就是说，输出的水仙花数必须大于等于m,并且小于等于n，如果有多个，则要求从小到大排列在一行内输出，之间用一个空格隔开; 如果给定的范围内不存在水仙花数，则输出no; 每个测试实例的输出占一行。 Sample Input 100 120 300 380 Sample Output no 370 371
数字的多次的迭代的算法的问题的解决的方式，用的是C程序的语言的编写的过程怎么做_course
20190409Problem Description For any positive integer n, we define function F(n) and XEN(n). For a collection S(n)={1,2,...,2n}, we select some numbers from it. For a selection, if each selected number could not be divided exactly by any other number in this selection, we will call the selection good selection. Further, we call a good selection best selection if the selection has more elements than any other good selection from S(n). We define F(n) the number of elements in the best selection from S(n). For example, n=2, F(n)=2. From the collection {1,2,3,4}, we can make good selection just like {2,3} or {3,4}, but we can't make any larger selection. So F(2) = 2. Then we pay attention to XEN(n). For every S(n), there are always some numbers could not be selected to make up any best selection. For instance, when n=2, 1 is always could not be chosen. What's more, for every S(n), there is a number k which satisfies that all the number, from 0 to k, are always could not be chosen. Now we let XEN(n)=k: n=2, F(n)=2, XEN(2)=1; n=4, F(n)=4, XEN(4)=1. You should write a program to calculate the value of F(n) and XEN(n) with a given number n. Input Your program is to read from standard input. There are multiple cases. For each case, one integer n (1 ≤ n ≤ 10^7) in a line. Output Output two integers with one space between them in one line per case. Sample Input 2 4 Sample Output 2 1 4 1
ASCII码排序 的一个程序题目_course
20200526Problem Description 输入三个字符后，按各字符的ASCII码从小到大的顺序输出这三个字符。 Input 输入数据有多组，每组占一行，有三个字符组成，之间无空格。 Output 对于每组输入数据，输出一行，字符中间用一个空格分开。 Sample Input qwe asd zxc Sample Output e q w a d s c x z
 82.2MB
微信小程序源码合集6.rar
20200904微信小程序源码，包含：图片展示、外卖点餐、小工具类、小游戏类、演绎博览、新闻资讯、医疗保健、艺术生活等源码。
YOLOv4目标检测实战：训练自己的数据集
20200426课程演示环境：Ubuntu需要学习Windows系统YOLOv4的同学请前往《Windows版YOLOv4目标检测实战：训练自己的数据集》，课程链接https://edu.csdn.net/course/detail/28748 YOLOv4来了！速度和精度双提升！ 与 YOLOv3 相比，新版本的 AP（精度） 和 FPS （每秒帧率）分别提高了 10% 和 12%。 YOLO系列是基于深度学习的端到端实时目标检测方法。本课程将手把手地教大家使用labelImg标注和使用YOLOv4训练自己的数据集。课程实战分为两个项目：单目标检测（足球目标检测）和多目标检测（足球和梅西同时检测）。 本课程的YOLOv4使用AlexAB/darknet，在Ubuntu系统上做项目演示。包括：安装YOLOv4、标注自己的数据集、整理自己的数据集、修改配置文件、训练自己的数据集、测试训练出的网络模型、性能统计(mAP计算和画出PR曲线)和先验框聚类分析。还将介绍改善YOLOv4目标训练性能的技巧。 除本课程《YOLOv4目标检测实战：训练自己的数据集》外，本人将推出有关YOLOv4目标检测的系列课程。请持续关注该系列的其它视频课程，包括： 《YOLOv4目标检测实战：人脸口罩佩戴识别》《YOLOv4目标检测实战：中国交通标志识别》《YOLOv4目标检测：原理与源码解析》
手把手实现Java图书管理系统（附源码）
20200116【超实用课程内容】 本课程演示的是一套基于Java的SSM框架实现的图书管理系统，主要针对计算机相关专业的正在做毕设的学生与需要项目实战练习的java人群。详细介绍了图书管理系统的实现，包括：环境搭建、系统业务、技术实现、项目运行、功能演示、系统扩展等，以通俗易懂的方式，手把手的带你从零开始运行本套图书管理系统，该项目附带全部源码可作为毕设使用。 1. 包含：项目源码、项目文档、数据库脚本、软件工具等所有资料 2. 手把手的带你从零开始部署运行本套系统 3. 该项目附带的源码资料可作为毕设使用 4. 提供技术答疑和远程协助指导 技术实现： 1. 后台框架：Servlet、JSP、JDBC、DbUtils 2. UI界面：EasyUI、jQuery、Ajax 3. 数据库：MySQL 项目截图： 1）系统登陆界面 2）管理系统 3）系统管理 更多Java毕设项目请关注【毕设系列课程】https://edu.csdn.net/lecturer/2104 【课程如何观看？】 PC端：https://edu.csdn.net/course/detail/27513 移动端：CSDN 学院APP（注意不是CSDN APP哦） 本课程为录播课，课程永久有效观看时长，大家可以抓紧时间学习后一起讨论哦~ 【学员专享增值服务】 源码开放 课件、课程案例代码完全开放给你，你可以根据所学知识，自行修改、优化
 学院 DB服务器使用mysql和redis高可用框架干货
 学院 深度学习工程师实战就业系列
 博客 python开发华为云应用侧进行设备接入
 博客 GRPC浅析completion_queue
 学院 c++专业课程之QT跨平台实战
 学院 Linux与shell
 学院 KETTLE工作中实用教程全部来自真实项目
 学院 软件测试工程师之Java编程入门自动化测试
 博客 自助式BI分析有哪些优势？
 博客 学习Spring Cloud与微服务之路三
 下载 2020最新已排序好的中国天气网城市编码Mysql
 下载 5G设备指导书.pdf
 学院 基于SSM框架智慧物业项目开发全程实录(全程实战附源码)
 博客 程序员正确看代码的方式
 下载 学生管理系统（struts2+hibernate+ajax+easyui）
 下载 ZXRAN(V5.35.20)ITRAN4&5G小区扩容指导书_R1.0.docx
 下载 5GNR高层信令流程.pdf
 学院 Java好师父
 博客 stm32 SysTick/EXTI/USART中断过程
 博客 MySql干货分享之索引
 下载 咸阳移动兴平南市700M测试报告20200810副本.docx
 学院 构建可视化研发工作流，制定规模化敏捷策略
 学院 基于ASP母婴用品商城网上购物商城系统毕业设计
 下载 中国移动2.6G5G信令流程详解.pptx
 博客 (2)python_numpy: numpy.ma.masked_invalid 与 numpy.ma.compress_rowcols 函数用法
 博客 Java中Short类型转换为Int类型是如何计算的？原码、反码、补码是什么？
 博客 白杨SEO：百度网站抓取异常的原因有哪些？有什么影响和解决方法？
 博客 Python3 （基础练习）猴子吃桃
 学院 【数据分析】第八周 数据可视化
 博客 利用SSRF漏洞内网探测来攻击Redis（通过curl命令 & gopher协议）