在四则算术运算表达式中，可以包含圆括号和方括号，而且还允许它们嵌套出现。试编写一个算法实现括号匹配。我的问题是 输入数据到数组后，不能进行匹配，不知道错在哪 求指导！

Question

#include<stdlib.h>
#include<string.h>
#include<stdio.h>

int match(char  *str)
{
    char stackMemroy[1024];
    int top = -1;
    int i = 0;
    while (str[i] != '\0')
    {
        if (str[i] == ')')//出
        {
            if (top > -1)
            {
                top--;
            }
            else
            {
                return -1;
            }
        }
        else if (str[i] == '(')//入
        {
            stackMemroy[++top] = str[i];
        }
        i++;
    }
    if (top == -1)
        return 0;
    else
        return 1;
}





int main()
{
    while(1)
    {
        char str[1024] = "";
        gets_s(str, 1024);
        /*scanf_s("%d", str);*/
        int result = match(str);
        if (result == 0)
        {
            printf("匹配\n");
        }
        else if (result == 1)
        {
            printf("多了左边括号\n");

        }
        else
        {
            printf("多了右边括号\n");
        }
    }
    return 0;
}

Answer 1

仅供参考：

#include<stdio.h>
#include<malloc.h>
#include<string.h>
#define STACK_INIT_SIZE 10
#define STACK_GROW_SIZE 5
#define ELEMTYPE char
#define OK 1
#define ERROR 0
typedef struct { /*建立一个栈的首结点*/
    ELEMTYPE * base;
    ELEMTYPE * top;
    int stacksize;
} SpStack;
int InitStack(SpStack *s) { /*建立空的栈并返回首地址*/
    s->base=((ELEMTYPE*)malloc(STACK_INIT_SIZE*sizeof(ELEMTYPE)));
    if (!s->base) return ERROR;
    s->top=s->base;
    s->stacksize=STACK_INIT_SIZE;
    return OK;
}
int StackEmpty(SpStack *s) { /*判断栈是否为空*/
    if (s->top==s->base) return OK;
    else                 return ERROR;
}
int Push(SpStack *s,ELEMTYPE e) { /*往栈顶插入元素即进栈*/
    if (s->top-s->base>=s->stacksize) { /*判断是否栈满*/
        s->base=((ELEMTYPE*)realloc(s->base,(s->stacksize+STACK_GROW_SIZE)*sizeof(ELEMTYPE)));
        if (!s->base) return ERROR;
        s->stacksize+=STACK_GROW_SIZE;
        s->top=s->base+s->stacksize;
    }
    *s->top++=e;
    return OK;
}
int Pop(SpStack *s,ELEMTYPE *e) { /*让栈顶元素依次输出即出栈*/
    if (StackEmpty(s)) return ERROR;
    *e=*(--s->top);
    return OK;
}
int Comp(ELEMTYPE a,ELEMTYPE b) {
    if ((a=='('&&b!=')')
      ||(a=='['&&b!=']')
      ||(a=='{'&&b!='}')) {
        return ERROR;
    } else return OK;
}
int Count(SpStack *s) {
    ELEMTYPE e[STACK_INIT_SIZE*2];
    ELEMTYPE e1;
    int i;

    InitStack(s);
    fgets(e,STACK_INIT_SIZE*2,stdin);
    if ('\n'==e[strlen(e)-1]) e[strlen(e)-1]=0;
    printf("%s\n",e);
    for (i=0;e[i]!='\0';i++) {
        switch (e[i]) {
        case '(':
        case '[':
        case '{':
            Push(s,e[i]);
            break;
        case ')':
        case ']':
        case '}':
            if (StackEmpty(s)) {
                printf("%*s↖右括号多余\n",i+1,"");
                return(ERROR);
            } else Pop(s,&e1);
            if (!Comp(e1,e[i])) {
                printf("%*s↖左右匹配出错\n",i+1,"");
                return(ERROR);
            }
        }
    }
    if (!StackEmpty(s)) {
        printf("%*s↖左括号多余\n",i,"");
        return(ERROR);
    } else {
        printf("匹配正确\n");
        return(OK);
    }
}
void main() {
    SpStack s;
    Count(&s);
    free(s.base);
}