C语言编程,如何根据一个小范围值区间,查找一个对应关系表,获得一个对应值呢
例如电压值为2000~2026(mv),
其对应功率值为-52(dB),如何用C语言编程,完成建表,查表,获得结果呢?

C语言编程,如何根据一个值,查找一个对应关系表,获得对应值呢?
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3条回答 默认 最新
- gg思无邪 2019-07-03 17:10关注
/*17点:一一对应版本*/ #include <stdio.h> #define NG (0xFF) //data structure typedef struct { int voltage; int power; }stVoltPowerTbl; //table const stVoltPowerTbl myTable[] = { {-19,1083}, {-18,1049}, {-17,1025}, {-16,996}, //add your data }; int Find(int voltage) { int Ret = NG; int i = 0; for(i=0;i<((sizeof(myTable))/(sizeof(stVoltPowerTbl)));i++) { if(myTable[i].voltage == voltage) { Ret = myTable[i].power; } } return Ret; } int main() { int Ret = 0; Ret = Find(-17); if(Ret != NG) { printf("power = %d \n",Ret); } else { printf("Error Voltage! \n"); } return 0; }
/*21点:根据范围求对应值版本*/ #include <stdio.h> #define NG (0xFF) //data structure typedef struct { int power; int minVoltage; int maxVoltage; }stVoltPowerTbl; //table const stVoltPowerTbl myTable[] = { {-55,2080,2094}, {-54,2060,2075}, {-52,2000,2026}, //add your data }; int Find(int voltage) { int Ret = NG; int i = 0; for(i=0;i<((sizeof(myTable))/(sizeof(stVoltPowerTbl)));i++) { if((myTable[i].minVoltage < voltage)&&(myTable[i].maxVoltage > voltage)) { Ret = myTable[i].power; } } return Ret; } int main() { int Ret = 0; Ret = Find(2001); if(Ret != NG) { printf("power = %d \n",Ret); } else { printf("Error Voltage! \n"); } return 0; }
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