qq_36437907
ybqq_0221
2019-07-06 16:41
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json对象的属性值获取不了？为undefined？

var data1 = {
                "raster_metainfo": [0,0,0,0,0,0,0],
                "navigation_metainfo": [0,0,0,0,0,0,0],
                "thematic_metainfo": [0,0,0,0,0,0,0],
                "text_metainfo":  [0,0,0,0,0,0,0],
                "video_metainfo":  [0,0,0,0,0,0,0],
                "database_metainfo": [0,0,0,0,0,0,0],
                "service_metainfo":  [0,0,0,0,0,0,0]
            }
            jsonData = JSON.stringify(data1);

            var a ='navigation_metainfo';
                        console.log(data1.a);
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4条回答 默认 最新

  • qq_35235940
    听楼一夜雨 2019-07-06 16:48
    已采纳

    你已经吧对象转成字符串了

    var data1 = {
                "raster_metainfo": [0,0,0,0,0,0,0],
                "navigation_metainfo": [0,0,0,0,0,0,0],
                "thematic_metainfo": [0,0,0,0,0,0,0],
                "text_metainfo":  [0,0,0,0,0,0,0],
                "video_metainfo":  [0,0,0,0,0,0,0],
                "database_metainfo": [0,0,0,0,0,0,0],
                "service_metainfo":  [0,0,0,0,0,0,0]
            };
            var a ='navigation_metainfo';
            console.log(data1.a);
            console.log(data1[a]);
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  • qq_36022290
    zhenyu-s5 2019-07-06 16:51

    你这么写肯定不对啊，编译成的是data1里面的a，但是data1.a根本不存在，写成这样就行了：
    console.log(data1[a]);

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  • qq_23126581 
    var data1 = {
                "raster_metainfo": [0,0,0,0,0,0,0],
                "navigation_metainfo": [0,0,0,0,0,0,0],
                "thematic_metainfo": [0,0,0,0,0,0,0],
                "text_metainfo":  [0,0,0,0,0,0,0],
                "video_metainfo":  [0,0,0,0,0,0,0],
                "database_metainfo": [0,0,0,0,0,0,0],
                "service_metainfo":  [0,0,0,0,0,0,0]
            }


               console.log(data1.navigation_metainfo);    //这个是可以取到整个navigation_metainfo 的数组
                             console.log(data1.navigation_metainfo[0]); //这个可以取到数组中的值，我这里取得是第一个值。
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  • wojiushiwo945you
    毕小宝 2019-07-06 18:38

    这里的 a 是一个变量，不能直接 .a 可以通过data1 [a] 获取这个属性值。

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