计算基本数值（平均值、标准差、中位数）

Question

import math
def getNum(ls):
    n=len(ls)
    return n
def mean(numbers):
    s=0
    for i in ls:
        i=float(i)
        s=s+i
    aver=s/numbers
    return aver
def dev(numbers, mean):
    a=0
    for i in ls:
        i=float(i)
        a=a+(i-mean)**2
    b=math.sqrt(float(a/numbers))    
    return b    
def median(numbers):
    ls2=sorted(ls)
    c=0
    if numbers%2==0:
        k=numbers/2
        for i in ls2[k,k+2]:
            i=float(i)
            c=c+i
        return c/2    
    else:
        k=(numbers+1)/2
        k=int(k)
        z=ls2[k-1]
        z=int(z)
        return z
    
m=input()
ls=[]
ls=m.split(",")
n=getNum(ls)
aver=mean(n)
q=dev(n,aver)
k=median(n) 
print("Average:{:.2f},Standard Deviation:{:.2f},Median:{}".format(aver,q,k))
    


Traceback (most recent call last):
  File "/545401477/p545401477", line 49, in <module>
    k=median(n) 
  File "/545401477/p545401477", line 32, in median
    for i in ls2[k,k+2]:
TypeError: list indices must be integers or slices, not tuple

上述错误有时会出现，而且当我输入1,3,6,9,2,5,1
错误输出：

Average:3.86,Standard Deviation:2.75,Median:3

期望输出：

Average:3.86,Standard Deviation:2.97,Median:3

Answer 1

import numpy as np
m=input()
ls=[]
ls=m.split(",")
for i in range(len(ls)):
    ls[i] = float(ls[i])
a = np.array(ls)
print(np.mean(a))
print(np.std(a))
print(np.median(a))

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如有用请采纳