请教怎么用python选取列表里的同一元素算平均数

Question

学生成绩表

Student_list = ['John, Jam, 2345, ITEC 1401: 65, BIT 2008: 72, BIT 1000: 79', 'Emma, Hu, 4321, ITEC 1401: 88, BIT 2008: 80, BIT 1000: 82', 'Kamil, Pavlowski, 4114, ITEC 1401: 92, BIT 2008: 90, BIT 1000: 95', 'Mike, Orr, 5432, ITEC 1401: 92, BIT 2008: 89, BIT 1000: 96' ]

当我输入
平均成绩 = calculate_class_ave(student_list, ‘ITEC 1401’) 84.5

怎么可以把每个ITEC1401后的数字加起来算平均数？
当我输入2345（第一个学生的学号）算出该学生的平均成绩
平均成绩=calculate_student_ave(student_list, 5432) 92.3

Answer 1

基本思路就是定义两个函数，分别计算班级平均和学生平均分，因为成绩表格式并不是太合理，所以应该考虑先整理成绩表，整理成字典格式处理起来会直观很多，尤其是数据量比较大的时候，当然基于当前数据，也可以直接计算，我给一种直接计算的方案：

def calculate_class_ave(stu_list, courceName):
    total = 0
    for stu_info in stu_list:
        stu_info_arr = [s.replace(' ','') for s in stu_info.split(",")]
        for info in stu_info_arr:
            if courceName.replace(' ','') in info:
                total += int(info.split(":")[1])
    print(f"课程{courceName}的班级平均成绩是：{total/len(stu_list)}")
    return total/len(stu_list)

def calculate_student_ave(stu_list, stu_no):
    total = 0
    for stu_info in stu_list:
        if stu_no in stu_info:
            stu_info_arr = [s.replace(' ','') for s in stu_info.split(",")]
            total = int(stu_info_arr[3].split(":")[1])+int(stu_info_arr[4].split(":")[1])+int(stu_info_arr[5].split(":")[1])
            break
    print(f"学生{stu_no}的平均成绩是{total/3}")
    return total/3


Student_list = ['John, Jam, 2345, ITEC 1401: 65, BIT 2008: 72, BIT 1000: 79', 'Emma, Hu, 4321, ITEC 1401: 88, BIT 2008: 80, BIT 1000: 82', 'Kamil, Pavlowski, 4114, ITEC 1401: 92, BIT 2008: 90, BIT 1000: 95', 'Mike, Orr, 5432, ITEC 1401: 92, BIT 2008: 89, BIT 1000: 96' ]
class_ave = calculate_class_ave(Student_list, 'ITEC 1401')
student_ave = calculate_student_ave(Student_list, '5432')

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