weixin_57808501 2022-04-20 14:28 采纳率: 47.4%
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已结题

发请求拿到的数据是扁平数组形式,怎么转换成el-tree树形式

问题遇到的现象和发生背景

发请求拿到的数据是一个数组

res:[
            {TENANT_ID_: "001",company_code: "00",company_name: "大坝1",id: "1",pid: "987"},
            {TENANT_ID_: "0010",company_code: "010",company_name: "大坝1-1",id: "1-1",pid: "987-1"},
            {TENANT_ID_: "00101",company_code: "010",company_name: "大坝1-1.1",id: "1-1.1",pid: "987-1.1"},
            {TENANT_ID_: "002",company_code: "00",company_name: "大坝2",id: "2",pid: "999"},
            {TENANT_ID_: "0020",company_code: "010",company_name: "大坝2-1",id: "2-1",pid: "999-1"},
            {TENANT_ID_: "00201",company_code: "010",company_name: "大坝2-1.1",id: "2-1.1",pid: "999-1.1"}
        ]

写的html 以及定义数据

<ht-tree 
                :tree-data="data" 
                :props="defaultProps"
                leaf-only = "true"
                include-half-checked = "true"
                @refresh="handleRefresh"   
                @node-click="handleNodeClick"
                >
            </ht-tree>

export default {
    data() {
      return {
          data:[],
            defaultProps: {
            children: 'children',
            label: 'company_name'
        },
          }
      }
}
我想要达到的结果

想要element el-tree树的效果一样,可以附上完整代码

img

  • 写回答

2条回答 默认 最新

  • Heerey525 前端领域新星创作者 2022-04-20 15:07
    关注

    简单写了下,从案例上可以满足,给你个思路

    let res = [
            { TENANT_ID_: "001", company_code: "00", company_name: "大坝1", id: "1", pid: "987" },
            { TENANT_ID_: "0010", company_code: "010", company_name: "大坝1-1", id: "1-1", pid: "987-1" },
            { TENANT_ID_: "00101", company_code: "010", company_name: "大坝1-1.1", id: "1-1.1", pid: "987-1.1" },
            { TENANT_ID_: "002", company_code: "00", company_name: "大坝2", id: "2", pid: "999" },
            { TENANT_ID_: "0020", company_code: "010", company_name: "大坝2-1", id: "2-1", pid: "999-1" },
            { TENANT_ID_: "00201", company_code: "010", company_name: "大坝2-1.1", id: "2-1.1", pid: "999-1.1" }
          ]
    
          let arr = []
    
          res.map(item => {
            item.children = []
            if (item.TENANT_ID_.length === 3) {
              arr.push(item)
            } else if (item.TENANT_ID_.length === 4) {
              let index = arr.findIndex(findChild => findChild.TENANT_ID_ === item.TENANT_ID_.substring(0, 3))
              arr[index].children.push(item)
            } else if (item.TENANT_ID_.length === 5) {
              let firstIndex = arr.findIndex(findChild => findChild.TENANT_ID_ === item.TENANT_ID_.substring(0, 3))
              let secondIndex = arr[firstIndex].children.findIndex(findChild => findChild.TENANT_ID_ === item.TENANT_ID_.substring(0, 4))
              arr[firstIndex].children[secondIndex].children.push(item)
            }
          })
    
      console.log('arr', arr)
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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  • 已结题 (查看结题原因) 5月23日
  • 已采纳回答 5月23日
  • 创建了问题 4月20日

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