C# 处理线程怎么处理在电脑很卡的状况？

Question

做了一个键盘输入方向控制 ，W A S D，30ms发送一次socket命令， 在电脑很卡的时候导致松开了按键，还是会一直发送按下的命令。请问这种情况怎么处理?

    private async void SendController() {
            try
            {

                StringBuilder msg = new StringBuilder();
                int w=0,a=0 ,s=0, d=0;
                while (AGVController)
                {
                    await Task.Delay(30);
                    msg.Clear();
                    Application.Current.Dispatcher.Invoke(delegate ()
                    {
                        if (Keyboard.IsKeyDown(Key.W))
                            w = 1;
                        else if (Keyboard.IsKeyUp(Key.W))
                            w = 0;

                        if (Keyboard.IsKeyDown(Key.S))
                            s = 1;
                        else if (Keyboard.IsKeyUp(Key.S) )
                            s = 0;

                        if (Keyboard.IsKeyDown(Key.A) )
                            a = 1;
                        else if (Keyboard.IsKeyUp(Key.A))
                            a = 0;

                        if (Keyboard.IsKeyDown(Key.D))
                            d = 1;
                        else if (Keyboard.IsKeyUp(Key.D))
                            d = 0;
                    });
                }
            }
            catch (Exception ex)
            {
                Log.WriteLog(ex);
            }
        }

Answer 1

https://www.cnblogs.com/sufei/p/3145333.html