编程实现,已有NXM的矩阵,对矩阵的全部元素做如下变换,若该数是素数则置0,否则置1。输出变换后的矩阵
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列宁格勒的街头 2022-04-21 23:40关注#include<stdio.h> int main() { int arr[500][500] = { 0 }; int n = 0; int m = 0; int i = 0; int j = 0; scanf("%d%d", &n, &m); for (i = 0; i < n; ++i) { for (j = 0; j < m; ++j) { scanf("%d", &arr[i][j]); } } for (i = 0; i < n; ++i) { for (j = 0; j < m; ++j) { //判断是否是素数 if (arr[i][j] == 0 || arr[i][j] == 1 || arr[i][j] == 2) { arr[i][j] = 1; } int num = 0; for (num = 2; num < arr[i][j]; ++num) { if (arr[i][j] % num == 0) { arr[i][j] = 1; } else { arr[i][j] = 0; } } } } for (i = 0; i < n; ++i) { for (j = 0; j < m; ++j) { printf("%d ", arr[i][j]); } printf("\n"); } return 0; }本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报 编辑记录