请求大佬支援！！想问问这个分治法的执行过程

Question

分治法里面的函数递归是如何执行的

maxSubArrayPart(nums,left,mid),

maxSubArrayPart(nums,mid+1,rig

ht),maxSubArrayAll(nums,left,mid,right)
这三个调用的结果是什么？

package com.student.play;

class Solution {
    public static int maxSubArray(int[] nums) {
        return maxSubArrayPart(nums,0,nums.length-1);
    }

    private static int maxSubArrayPart(int[] nums,int left,int right){
        if(left==right){
            return nums[left];
        }
        int mid=(left+right)/2;
        return Math.max(
            maxSubArrayPart(nums,left,mid),
            Math.max(
                maxSubArrayPart(nums,mid+1,right),
                maxSubArrayAll(nums,left,mid,right)
            )
        );
    }

    //左右两边合起来求解
    private static int maxSubArrayAll(int[] nums,int left,int mid,int right){
        int leftSum=Integer.MIN_VALUE;
        int sum=0;
        for(int i=mid;i>=left;i--){
            sum+=nums[i];
            if(sum>leftSum){
                leftSum=sum;
            }
        }
        sum=0;
        int rightSum=Integer.MIN_VALUE;
        for(int i=mid+1;i<=right;i++){
            sum+=nums[i];
            if(sum>rightSum){
                rightSum=sum;
            }
        }
        return leftSum+rightSum;
    }

    public static void main(String args[]){
        int nums[] = {-2,1,-3,4,-1,2,1,-5,4};
        System.out.println(maxSubArray(nums));
    }
}

Answer 1

https://www.cnblogs.com/jiaxin359/p/9270741.html