char * names[6] = {"Guanyu", "Zhangfei", "Zhaoyun", "Machao", "Huangzhong", "Liubei"};
字典中的顺序进行排序
- 写回答
- 好问题 0 提建议
- 关注问题
- 邀请回答
-
1条回答 默认 最新
qfl_sdu 2022-04-25 15:54关注如下:
#include <stdio.h> #include <string.h> int main() { int i, j; char* temp; char* names[6] = { (char*)"Guanyu", (char*)"Zhangfei", (char*)"Zhaoyun", (char*)"Machao", (char*)"Huangzhong", (char*)"Liubei" }; //冒泡排序 for (i = 0; i < 5; i++) { for (j = 0; j < 5 - i; j++) { if (strcmp(names[j] , names[j + 1]) > 0) { temp = names[j]; names[j] = names[j + 1]; names[j + 1] = temp; } } } //输出 for (i = 0; i < 6; i++) printf("%s\n", names[i]); return 0; }本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报