C++初学者静态数据成员部分

Question

#include <iostream>
#include <string.h>
using namespace std;
class Student{
private:
    char name[20];
    int number;
    int score;
public:
    friend int Find(Student *s,int x);
    void print(){
    cout<<number<<"  "<<score<<endl;}
     Student(char na[],int x,int y);
};
int main()
{
    int no,i;
    Student s[3]={Student("zangsan",91001,89),Student("wangmimng",91002,92),Student("jiajing",91003,65)};
    cin>>no;
    i=Find(s,no);
    if(i==-1)
        cout<<"Error"<<endl;
    else
        s[i].print();
    return 0;
}
int Find(Student *s,int x)
{
    int i,n=0,k=-1;
    for(i=0;i<=2;i++)
    {
        if(s->number==x)
            {return i;
             break;}
        else
           {
               s++;
               n++;
           }
    }
    if(n==i)
    return k;
}
Student::Student(char na[],int x,int y)
{
    strcpy(name,na);
    number=x;
    score=y;
 
}
 

这个上面两张是要求，下面是我写根据给的条件的大致代码，静态数据成员这里写不下去了，还有在输入信息循环这里老有问题，我刚接触C++，其中有好多低级问题，麻烦看一下，给个正确的，方法，过程

Answer 1

使用一个结构体定义student，然后使用一个vector进行存储所有的学生信息。最后取所有学生成绩进行相加，最后输出就行

#include <iostream>
#include <string.h>
#include <vector>
using namespace std;
struct Student{
    int Id=0;
    string Name="";
    int Achievement=0;
};

int main()
{
    vector<Student> students;
    int n;
    cout<<"输入学生数量";
    cin>>n;
    cout<<"请输入学生编号,名字,成绩";
    for(int i=0;i<n;++i)
    {
        int id,achievement;
        string name;
        cin>>id>>name>>achievement;
        Student student;
        student.Id=id;
        student.Name=name;
        student.Achievement=achievement;
        students.push_back(student);
    }
    int Count=0;
    for(int i=0;i<students.size();++i)
    {
        Count+=students[i].Achievement;
    }
    cout<<"总成绩:"<<Count<<endl;
    for(int i=0;i<students.size();++i)
    {
        cout<<students[i].Id<<" "<<students[i].Name<<" "<<students[i].Achievement<<endl;
    }
}