c++11 lambda 我想求10个随机数的平方和 中间那一点不会写的 怎么写呢

Question

c++11 lambda 我想求10个随机数的平方和 中间那一点不会写的 怎么写呢

#include <bits/stdc++.h>
using namespace std;
void myPrintf(int val)
{
    cout << val << " ";
}
int main()
{
    int a[24];
    vector<int> sourceVector;
    sourceVector.resize(10);
    srand((unsigned)time(NULL));
    for(int i=0;i<10;i++)
    {
        a[i]=rand()%100;
        sourceVector.push_back(a[i]); 
    }
//    int res=0;
//    generate(sourceVector.begin(), sourceVector.end(), [&res](int x) {
//        res=x*x;
//        return res;
//    });
    for_each(sourceVector.begin(), sourceVector.end(), myPrintf);
    cout << endl;
}

Answer 1

遍历每次平方加到res里，之后输出

    #include <bits/stdc++.h>
    using namespace std;
    void myPrintf(int val)
    {
        cout << val << " ";
    }
    int main()
    {
        int a[24];
        vector<int> sourceVector;
        sourceVector.resize(10);
        srand((unsigned)time(NULL));
        for(int i=0;i<10;i++)
        {
            a[i]=rand()%100;
            sourceVector.push_back(a[i]);
        }
        int res=0;
         vector<int>::iterator i1;
        for (i1 = sourceVector.begin(); i1 != sourceVector.end(); ++i1) {
           res+=*i1**i1;
        }
        cout<<res<<endl;
        for_each(sourceVector.begin(), sourceVector.end(), myPrintf);
        cout << endl;
    }

Answer 2

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