设计一个函数arithmetic, 通过调用该函数，对输入的两个整数a和b依此求出其和、差、积、余数。要求用函数指针作为函数参数。

Question

问一下大家，这个哪里错了？正确的是怎样的？（下面这个是用扫描文字来的，请看图片）#include<stdio.h>
main()
{ int add (int, int);
int sub(int,int)
int mul (int, int)
irt fmod(int, int):
void arithmetic(int, int,int (*fun) (int,int)): int a,b
printf("input a and b:");
scanf ("%d,%d",&a,&b):
printf'"sum=");arithmetic(a,b, add);
printf("difference="):arithmetic(a,b,sub); printf("product="): arithmetic(a,b,mul): printf("remaindern=");arithmetic(a,b, fmod): int add(int x,int y)
antz;
Z=xty:
rerturn(z)
int sub(int x,int y) {intz
Z=X一F
return (z)
int mul(int x,int y) [intz:
z=x*y;
return(z)
Eint fmod(int x,int y)
{intz:
z=x%y:
return(z):
avoid arithmetic(int x, int y,int (*fun) (int,int)) { int result
reslt=(*fun) (x,y):
printf("%d\n", result):

Answer 1

#include<stdio.h>
int main()
{
    int add(int, int);
    int sub(int, int);
    int mul(int, int);
    int fmod(int, int);
    void arithmetic(int, int, int (*fun) (int, int));
    int a, b;
    printf("input a and b:");
    scanf("%d,%d", &a, &b);
    printf("sum="); arithmetic(a, b, add);
    printf("difference="); arithmetic(a, b, sub); printf("product=");
    arithmetic(a, b, mul); printf("remaindern="); arithmetic(a, b, fmod);
}
        int add(int x, int y) {
            int z;
            z = x + y;
            return(z);
        }
        int sub(int x, int y) {
            int z;
            z = x - y;
            return (z);
        }
        int mul(int x, int y) {
            int z;
            z = x * y;
            return(z);
        }
            int fmod(int x, int y)
        {
            int z;
            z = x % y;
            return(z);
        }
        void arithmetic(int x, int y, int (*fun) (int, int)) {
            int result;
            result = (*fun) (x, y);
            printf("%d\n", result);
        }