本人刚学Django,这是一个临时程序,本来想实现通过url查找用户信息,并且在代码片段中添加了跳转链接
urls.py
from . import views
from django.conf.urls import url, include
urlpatterns = [
url(r'^$',views.index,name='index'),
url(r'^(?P<name_id>\d+)/$',views.names,name='names'),
]
views.py
from django.shortcuts import render
from .models import Name
# Create your views here.
def index(request):
name = Name.objects.all()
context = {'names':name}
return render(request,'index.html',context)
def names(request, name_id):
name = Name.objects.get(id=name_id)
context = {'name':name}
return render(request,'names.html',context)
index.py
<p>INDEX</p>
<!--这里想通过无序列表将用户名列出来-->
<ul>
{% for name in names %}
<!--本来想在此处插入跳转链接的,但是出错-->
<li><a href="{% url 'testing:names' %}">{{ name }}</a></li>
{% empty %}
<li>NOTHING HERE</li>
{% endfor %}
</ul>
以上就是主要的代码
报错如下: