收起
望采纳,谢谢!
def coding(s): n = len(s) #print(n) if s.count("0" ) == n: return 'A' elif s.count('1') == n: return 'B' else: return 'C' + ' '+ s[:n//2] + ' '+ s[n//2:] s = input() print(coding(s))
报告相同问题?