计算 s=1−1/2+1/3−1/4+…+1/99−1/100
用for循环
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溪风沐雪 2022-05-05 13:08关注result = 0 for i in range(1,101): if i%2==0: result = result - 1/i else: result = result + 1/i print(result)本回答被题主选为最佳回答 , 对您是否有帮助呢?评论 打赏 举报解决 1无用
result = 0
for i in range(1,101):
if i%2==0:
result = result - 1/i
else:
result = result + 1/i
print(result)