为什么在不输入整数的情况下,输出语句会一直执行,直到栈溢出,不是只在catch里调用了一次print方法嘛
import java.util.Scanner;
public class test {
Scanner myScanner = new Scanner(System.in);
int i;
public void print() {
try {
System.out.println("请输入整数:");
i = myScanner.nextInt();
} catch (Exception e) {
print();
}
}
}
请输入整数:
请输入整数:
请输入整数:
请输入整数:
请输入整数:
请输入整数:
请输入整数:
Exception in thread "main" java.lang.StackOverflowError
at java.util.regex.Pattern$GroupTail.match(Pattern.java:4731)
at java.util.regex.Pattern$GroupTail.match(Pattern.java:4731)
at java.util.regex.Pattern$GroupTail.match(Pattern.java:4731)
at java.util.regex.Pattern$GroupTail.match(Pattern.java:4731)
at java.util.regex.Pattern$BranchConn.match(Pattern.java:4582)
at java.util.regex.Pattern$GroupTail.match(Pattern.java:4731)
at java.util.regex.Pattern$Curly.match2(Pattern.java:4325)
at java.util.regex.Pattern$Curly.match(Pattern.java:4252)
at java.util.regex.Pattern$GroupHead.match(Pattern.java:4672)
at java.util.regex.Pattern$Branch.match(Pattern.java:4618)
at java.util.regex.Pattern$GroupHead.match(Pattern.java:4672)
at java.util.regex.Pattern$GroupHead.match(Pattern.java:4672)
at java.util.regex.Pattern$Ques.match(Pattern.java:4196)
at java.util.regex.Pattern$GroupHead.match(Pattern.java:4672)
at java.util.regex.Pattern$GroupHead.match(Pattern.java:4672)
at java.util.regex.Pattern$Branch.match(Pattern.java:4618)
at java.util.regex.Matcher.match(Matcher.java:1270)
at java.util.regex.Matcher.matches(Matcher.java:604)
at java.util.Scanner.getCompleteTokenInBuffer(Scanner.java:963)
at java.util.Scanner.next(Scanner.java:1476)
at java.util.Scanner.nextInt(Scanner.java:2117)
at java.util.Scanner.nextInt(Scanner.java:2076)
at com.exception_.test.print(test.java:12)
at com.exception_.test.print(test.java:14)
at com.exception_.test.print(test.java:14)