MySQL 宋红康 章节练习题第四章

Question

# 1.选择工资不在5000到12000的员工的姓名和工资 ac
SELECT last_name salary(1+NULL(commission_pct,0)) salary 
WHERE(salary*(1+IFNULL(commission_pct,0)) NOT BETWEEN 5000 AND 12000);
# 2.选择在20或50号部门工作的员工姓名和部门号ac
SELECT last_name name,department_id FROM employees WHERE department_id IN (20,50);
# 3.选择公司中没有管理者的员工姓名及job_id  ac
SELECT last_name name,job_id FROM employees WHERE manager_id IS NULL;
# 4.选择公司中有奖金的员工姓名，工资和奖金级别ac
SELECT last_name name,salary*(1+IFNULL(commission_pct,0)) "工资",commission_pct "奖金级别" FROM employees
WHERE commission_pct IS NOT null;
# 5.选择员工姓名的第三个字母是a的员工姓名ac
SELECT last_name name FROM employees WHERE last_name LIKE '__a%';
# 6.选择姓名中有字母a和k的员工姓名 ac
SELECT last_name name FROM employees WHERE last_name LIKE '%a%'AND last_name LIKE '%k%';
# 7.显示出表 employees 表中 first_name 以 'e'结尾的员工信息 ac
SELECT first_name name FROM employees WHERE first_name  LIKE '%e';
# 8.显示出表 employees 部门编号在 80-100 之间的姓名、工种 ac
SELECT last_name name,job_id "工种" FROM employees WHERE department_id BETWEEN 80 and 100;
# 9.显示出表 employees 的 manager_id 是 100,101,110 的员工姓名、工资、管理者id*/ac
SELECT last_name name,salary,manager_id FROM employees WHERE manager_id in (100,101,110);
SELECT DISTINCT manager_id FROM employees;