#include<stdio.h>
struct
{
int year;
int month;
int day;
}date;
int main()
{
int days(struct date);
int n;
printf("输入年 月 日\n");
scanf("%d %d %d",&date.year,&date.month,&date.day);
n=days(date);
printf("该日是本年第%d天\n",n);
return 0;
}
int days(struct date)
{
int m,i;
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
int b[12]={31,29,31,30,31,30,31,31,30,31,30,31};
m=0;
if((date.year%4==0&&date.year%100!=0)||(date.year%400==0))
{
for(i=0;i<date.month-1;i++)
m=m+b[i];
}
else
{
for(i=0;i<date.month-1;i++)
m=m+a[i];
}
m=m+date.day;
return (m);
}
编写一函数,利用结构体变量计算某日是改年的第几天,代码错了,但我不知道该怎么修改
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1条回答 默认 最新
树下等苹果 2022-05-08 14:31关注date是全局变量,不用传给函数
#include<stdio.h> struct date { int year; int month; int day; }date; int main() { int days(); int n; printf("输入年 月 日\n"); scanf_s("%d %d %d", &date.year, &date.month, &date.day); n = days(); printf("该日是本年第%d天\n", n); return 0; } int days() { int m, i; int a[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 }; int b[12] = { 31,29,31,30,31,30,31,31,30,31,30,31 }; m = 0; if ((date.year % 4 == 0 && date.year % 100 != 0) || (date.year % 400 == 0)) { for (i = 0; i < date.month - 1; i++) m = m + b[i]; } else { for (i = 0; i < date.month - 1; i++) m = m + a[i]; } m = m + date.day; return (m); }本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报