python的抓狐狸游戏的修改

Question

怎么修改这个代码，使他是以函数的方式调用，而且这个函数的参数：洞口数和抓取数（默认为10）

Answer 1

没搞懂你具体要干啥，不过挺好玩的

import random
day = 10
hole = [0, 0, 0, 0, 0]
foxp = random.randint(0, 4)
hole[foxp] = 1

def FM(hole):
    move = random.randint(0, 1)
    if move == 1 and hole[4] != 1:
        old = hole.index(1)
        hole[old] = 0
        hole[old + 1] = 1

def game(day, hole):
    x = 0
    while x < day:
        while True:
            try:
                playerNum = int(input('请输入你想打开洞的编号（1，2，3，4，5）：')) - 1
                if 0 <= playerNum <= 4:
                    break
            except Exception:
                print('输入错误，请重新输入！')
        if hole[playerNum] == 1:
            print('恭喜你在第{}天的{}号洞抓到了狐狸！'.format(x+1, playerNum+1))
            break
        else:
            print('第', x+1 ,'天',playerNum+1,'号洞没有狐狸')
            FM(hole)
        x += 1
    if x == day:
        print('超过十天，失败了')
        
game(day, hole)