json_decode出错，会php的高手告诉我错误的地方怎么写？谢谢

Question

<?php
//$id = $_GET['id'];
$url="http://d532519556-1259225818.cos.ap-chengdu.myqcloud.com/92580.json";
$info=file_get_contents($url);
$address=json_decode($info,true);
if(empty($address)){ exit('接口返回address数据格式错误'); }
$json=$address["live"][0]["urllist"];
if(empty($json)){ exit('接口返回json数据格式错误'); }
echo $json;
//header('location:'.$address);
?>

抓取网址中内容的视频链接，如图：

现在执行代码时候，报错“接口返回address数据格式错误”，但是不知道“$address=json_decode($info,true);”
这句哪里错误？请各位php高手告诉我怎么写？谢谢！

Answer 1

1. 网页编码不是UTF-8

2. 解决方法: 先转换编码,替换一些特殊字符,在进行json解析.

   $url="http://d532519556-1259225818.cos.ap-chengdu.myqcloud.com/92580.json";
       $text = file_get_contents($url);
       define('UTF32_BIG_ENDIAN_BOM', chr(0x00) . chr(0x00) . chr(0xFE) . chr(0xFF));
       define('UTF32_LITTLE_ENDIAN_BOM', chr(0xFF) . chr(0xFE) . chr(0x00) . chr(0x00));
       define('UTF16_BIG_ENDIAN_BOM', chr(0xFE) . chr(0xFF));
       define('UTF16_LITTLE_ENDIAN_BOM', chr(0xFF) . chr(0xFE));
       define('UTF8_BOM', chr(0xEF) . chr(0xBB) . chr(0xBF));
       $first2 = substr($text, 0, 2);
       $first3 = substr($text, 0, 3);
       $first4 = substr($text, 0, 3);
       $encodType = "";
       if (UTF8_BOM == $first3) {
           $encodType = 'UTF-8 BOM';
       } else if (UTF32_BIG_ENDIAN_BOM == $first4) {
           $encodType = 'UTF-32BE';
       } else if (UTF32_LITTLE_ENDIAN_BOM == $first4) {
           $encodType = 'UTF-32LE';
       } else if (UTF16_BIG_ENDIAN_BOM == $first2) {
           $encodType = 'UTF-16BE';
       } else if (UTF16_LITTLE_ENDIAN_BOM == $first2) {
           $encodType = 'UTF-16LE';
       }
   
       //下面的判断主要还是判断ANSI编码的·
       if ('' == $encodType) {
           //即默认创建的txt文本-ANSI编码的
           $content = iconv("GBK", "UTF-8", $text);
       } else if ('UTF-8 BOM' == $encodType) {
           //本来就是UTF-8不用转换
           $content = $text;
       } else {
           //其他的格式都转化为UTF-8就可以了
           $content = iconv($encodType, "UTF-8", $text);
       }
       $address=json_decode( preg_replace('/[\x00-\x1F\x80-\xFF]/', '', $content), true );
       if(empty($address)){ exit('接口返回address数据格式错误'); }
       $json=$address["live"][0]["urllist"];
       if(empty($json)){ exit('接口返回json数据格式错误'); }
       echo $json;die;