绘制函数f(x)=sin(x)，区间为[0,2*pi],间隔

Question

二。（1）生成一个只有一个图形的图片，并绘制函数f(x)=sin(x)，区间为[0,2pi]间隔适当即可
（2）在改变x轴位置上的0,pi/2,pi,3pi/2,2*pi刻度标签为"one","two",“three”“four”,"five"
（3）适当增加轴标签和标题，并显示
想问这个问题怎么写

Answer 1

from matplotlib import pyplot as plt
import numpy as np

x = np.linspace(0, 2*np.pi, 200, endpoint=True)
y = np.sin(x)

plt.figure('sin(x)图像')
plt.plot(x,y)
plt.title('y = sin(x)')
plt.xticks(ticks=np.linspace(0, 2*np.pi, 5, endpoint=True), labels=["one","two","three","four","five"])
plt.xlabel('x')
plt.ylabel('y = sin(x)')
plt.show()