如何获取列表子字典对应的键值？

Question

s=[{'a':'33', 'b':'ee', 'c':'55'}, {'a':'tt', 'b':'bb', 'c':'aa'}]
list = []
a = list.append(x[0]['a'] for x in s)
print (a)

期望输出 33 tt

Answer 1

list.append的返回值是None，所以你打印a是没有用的

s=[{'a':'33', 'b':'ee', 'c':'55'}, {'a':'tt', 'b':'bb', 'c':'aa'}]
l = [ x['a'] for x in s]
print(l)