两数组对象对比,如果相同就放到A数组对象内,

Question

      const Alist = [{ name: 'aa', }, { name: 'bb', }, { name: 'cc' },]
      const Blist = [{ name: 'aa', id: 1 }, { name: 'bb', id: 2 }, { name: 'bb', id: 3 }, { name: 'cc', id: 4 }, { name: 'aa', id: 5 },]

怎么把上面2组数组对比后 得到下面的新数组

      const AlistNew = [{ name: 'aa', list: [{ id: 1 }, { id: 5 }] }, { name: 'bb', list: [{ id: 2 }, { id: 3 }] }, { name: 'cc', list: [{ id: 4 }] },]

Answer 1

const Alist = [
        { name: 'aa', }, 
        { name: 'bb', }, 
        { name: 'cc' },
    ]
    const Blist = [
        { name: 'aa', id: 1 }, 
        { name: 'bb', id: 2 }, 
        { name: 'bb', id: 3 }, 
        { name: 'cc', id: 4 }, 
        { name: 'aa', id: 5 }
    ]
     Alist.forEach((v,i)=>{
         Blist.forEach((vv,ii)=>{
             if(v.name==vv.name){
                 if(!v.list){
                     v.list=[]
                 }
                v.list.push({
                    id:vv.id
                })
             }
         })
     })