这是python 的 Bug么？ random随机数处理

Question

问题遇到的现象
[6, 5, 8, 6, 2, 5, 0, 2, 7, 3]
运算后的： [6, 5, 8, 6, 2, 5, 0, 2, 7, 3] -bug 这个3 没有执行 + 2
[4, 2, 5, 6, 6, 0, 5, 6, 5, 4]
[5, 1, 0, 3, 4, 9, 0, 4, 9, 5]
运算后的： [5, 1, 0, 5, 4, 9, 0, 4, 9, 5]
[6, 9, 1, 6, 6, 5, 9, 1, 5, 9]
[5, 0, 3, 3, 9, 3, 0, 5, 1, 9]
运算后的： [5, 0, 3, 5, 9, 5, 0, 5, 1, 9]
[1, 3, 2, 0, 0, 7, 0, 4, 0, 1]
运算后的： [1, 5, 2, 0, 0, 7, 0, 4, 0, 1]
[3, 2, 6, 4, 6, 8, 7, 3, 4, 9]
运算后的： [3, 2, 6, 4, 6, 8, 7, 5, 4, 9]
[8, 6, 4, 8, 0, 7, 4, 4, 7, 7]

问题相关代码

import random

# while True:
for i in range(0, 10):
    xs = []
    for i in range(0, 10):
        x = random.randint(0, 9)
        xs.append(x)
    print(xs)

    if 3 in xs:
        for i in xs:
            if xs[i] == 3:
                xs[i] += 2
        print('运算后的：', xs)

运行结果

[6, 5, 8, 6, 2, 5, 0, 2, 7, 3]
运算后的： [6, 5, 8, 6, 2, 5, 0, 2, 7, 3] bug在这里 有个 3 没有执行 + 2
[4, 2, 5, 6, 6, 0, 5, 6, 5, 4]
[5, 1, 0, 3, 4, 9, 0, 4, 9, 5]
运算后的： [5, 1, 0, 5, 4, 9, 0, 4, 9, 5]
[6, 9, 1, 6, 6, 5, 9, 1, 5, 9]
[5, 0, 3, 3, 9, 3, 0, 5, 1, 9]
运算后的： [5, 0, 3, 5, 9, 5, 0, 5, 1, 9]
[1, 3, 2, 0, 0, 7, 0, 4, 0, 1]
运算后的： [1, 5, 2, 0, 0, 7, 0, 4, 0, 1]
[3, 2, 6, 4, 6, 8, 7, 3, 4, 9]
运算后的： [3, 2, 6, 4, 6, 8, 7, 5, 4, 9]
[8, 6, 4, 8, 0, 7, 4, 4, 7, 7]

这是哪里写出了bug么？

Answer 1

你代码写错了
for i in xs:
改成for i in range(len(xs))