weixin_54219174 2022-05-29 11:33 采纳率: 50%
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PHP 怎么修改这段代码 让下拉菜单点击提交后可以跳转到相应页面

img


<?php
    $link = mysqli_connect('localhost','root','root','db_chengji','3306');
    mysqli_set_charset($link,'utf8');
    $sql1 = "select * from `tb_info` ORDER BY `id` ASC ";
    $mysqli_result1 = mysqli_query($link,$sql1);
    $recount = mysqli_num_rows($mysqli_result1);
    $pagesize = 7;
    $pageno = $_GET['pageno'] ? $_GET['pageno'] : 1;
    $pagecount = ceil($recount / $pagesize);
    $offset = ($pageno-1) * $pagesize;
    $sql = "select * from `tb_info` ORDER BY `id` ASC limit $offset,$pagesize";
    $mysqli_result1 = mysqli_query($link,$sql);
    echo "<table align='center' border='1' style='border-collapse: collapse' width='450'>";
    echo "<tr>";
    while($field = mysqli_fetch_field($mysqli_result1))
        echo "<th>".$field->name."</th>";
    echo "</tr>";
    $j = 0;
    while($row = mysqli_fetch_object($mysqli_result1)) {
        $j++;
        echo "<tr>";
        echo "<td>" . $row->id . "</td>";
        echo "<td>" . $row->name . "</td>";
        echo "<td>" . $row->sex . "</td>";
        echo "<td>" . $row->class . "</td>";
        echo "<td>" . $row->hobby . "</td>";
        echo "</tr>";
    }

    for($i = $j;$i<$pagesize;$i++){
        echo "<tr>";
        echo "<td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td>";
        echo "</tr>";

    }
    $arr=array();
    echo "<tr><th colspan='5'>";
    for($pageno = 1;$pageno <= $pagecount;$pageno ++){
        echo "<a href='?pageno=$pageno'>$pageno</a>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;";
        $arr[]=$pageno;
    }
    //print_r($arr);
    echo "<select name='sel'>";
    foreach($arr as $key=>$value){
        echo "<option value=\"key\">第{$value}页</option>";
    }
    echo"<form name='form1' method='post' action=''>
            <input type='submit' name='bt' value='提交' >
            <a href='?pageno=$pageno'>
        </form>";
    if(isset($_POST['bt']))
        
echo "</select>";
    echo "</th></tr>";
    echo "</table>";

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1条回答 默认 最新

  • PHP技术栈 2022-05-30 13:16
    关注

    看了一下,主要是两个问题:
    1、select下拉选择放在form表单外边了,导致下单选择的信息没有正常提交;
    2、表单用的是POST提交,上边开头没有写接收POST表单信息。
    以下是我改过之后代码,你试一下:

    <?php
        $link = mysqli_connect('localhost','root','root','db_chengji','3306');
        mysqli_set_charset($link,'utf8');
        $sql1 = "select * from `tb_info` ORDER BY `id` ASC ";
        $mysqli_result1 = mysqli_query($link,$sql1);
        $recount = mysqli_num_rows($mysqli_result1);
        $pagesize = 7;
        //检测提交类型 POST/GET
        $pagenoType = isset($_POST['sel'])?$_POST['sel']:$_GET['pageno'];
        $pageno = $pagenoType ? $pagenoType : 1;
        $pagecount = ceil($recount / $pagesize);
        $offset = ($pageno-1) * $pagesize;
        $sql = "select * from `tb_info` ORDER BY `id` ASC limit $offset,$pagesize";
        $mysqli_result1 = mysqli_query($link,$sql);
        echo "<table align='center' border='1' style='border-collapse: collapse' width='450'>";
        echo "<tr>";
        while($field = mysqli_fetch_field($mysqli_result1))
            echo "<th>".$field->name."</th>";
        echo "</tr>";
        $j = 0;
        while($row = mysqli_fetch_object($mysqli_result1)) {
            $j++;
            echo "<tr>";
            echo "<td>" . $row->id . "</td>";
            echo "<td>" . $row->name . "</td>";
            echo "<td>" . $row->sex . "</td>";
            echo "<td>" . $row->class_name . "</td>";
            echo "<td>" . $row->hobby . "</td>";
            echo "</tr>";
        }
     
        for($i = $j;$i<$pagesize;$i++){
            echo "<tr>";
            echo "<td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td><td>&nbsp;</td>";
            echo "</tr>";
     
        }
        $arr=array();
        echo "<tr><th colspan='5'>";
        for($pageno = 1;$pageno <= $pagecount;$pageno ++){
            echo "<a href='?pageno=$pageno'>$pageno</a>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;";
            //使数组的键名与值相同
            $arr[$pageno]=$pageno;
        }
        //print_r($arr);
        echo"<form name='form1' method='POST' action=''>";
        echo "<select name='sel'>";
        foreach($arr as $key=>$value){
            if(isset($_POST['sel']) && !empty($_POST['sel']) && $value == $_POST['sel']){
                echo "<option value=\"$key\" selected='selected'>第{$value}页</option>";
            }else{
                echo "<option value=\"$key\">第{$value}页</option>";        
            }
        }
        echo "<input type='submit' name='bt' value='提交' >
                <a href='?pageno=$pageno'>
            </form>";
        if(isset($_POST['bt']))
            
        echo "</select>";
        echo "</th></tr>";
        echo "</table>";
    ?>
    
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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问题事件

  • 系统已结题 6月10日
  • 已采纳回答 6月2日
  • 修改了问题 5月29日
  • 创建了问题 5月29日

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