dic = {0:0, 1:0, 2:0, 3:0, 4:0, 5:0, 6:0, 7:0, 8:0, 9:0}
lst = map(int, input().split())
for i in lst:
dic[i] += 1print(' '.join([str(i) for i in dic.values()]))
weixin_39586395的博客方法一:利用字典的get函数,get...values=[1,2,3,2,3,1,4]values_cnt={}for value in values:value_cnt[value]=values_cnt.get(value,0)+1方法三:定义一个新的计数字典,用来放元素及其个数。为了防止产生异常,...
如下所示: lis = [12,34,456,12,34,66,223,12,5,66,12,23,66,12,66,5,456,12,66,34,... #进行统计,生成二维列表 b = [] for i in c: num = 0 for j in range(len(lis)): if lis[j] == i: num += 1 a = [] a.