python定义一个Rectangle类(矩形)

Question

python定义类属性，对象属性，实现构造方法和析构方法，完成类属性和对象属性的设置

Answer 1

比较麻烦的是怎么判断四边形的形状，如果与坐标不平行，就得计算出所有边长以及角度再比较了

from pygame import Rect


class Rectangle():
    num = 0
    def __init__(self, topleft, topright, bottomright, bottomleft):
        self.tl = topleft
        self.tr = topright
        self.br = bottomright
        self.bl = bottomleft
        Rectangle.num += 1
    
    def gettype(self):
        top = (self.tr[1]-self.tl[1])**2 + (self.tr[0]-self.tl[0])**2
        right = (self.tr[1]-self.br[1])**2 + (self.tr[0]-self.br[0])**2
        bottom = (self.br[1]-self.bl[1])**2 + (self.br[0]-self.bl[0])**2
        left = (self.tl[1]-self.bl[1])**2 + (self.tl[0]-self.bl[0])**2
        top_bottom = (self.tr[1]-self.tl[1])*(self.br[0]-self.bl[0])==(self.br[1]-self.bl[1])*(self.tr[0]-self.tl[0])
        left_right = (self.tr[1]-self.br[1])*(self.tl[0]-self.bl[0])==(self.tr[0]-self.br[0])*(self.tl[1]-self.bl[1])
        parallel = top_bottom+left_right
        if parallel == 2:
            diagonal = (self.tr[1]-self.bl[1])**2 + (self.tr[0]-self.bl[0])**2
            if bottom + right == diagonal:
                if top == left:
                    print('正方形')
                else:
                    print('长方形')
            else:
                print('平行四边形')
        elif parallel == 1:
            print('梯形')
        else:
            print('其他')

a = Rectangle((0,0),(0,2),(4,2),(4,0))
a.gettype()