eclipse android获取网页源码

Question

定义了一个按钮btn 的onClick=“click”
ublic class MainActivity extends Activity {

private EditText et;
private TextView tv;

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    et = (EditText) findViewById(R.id.et);
    tv = (TextView) findViewById(R.id.btn);


}

public void click(View v){
    String path=et.getText().toString().trim();
    try {
        URL url=new URL(path);
        HttpURLConnection con=(HttpURLConnection) url.openConnection();
        con.setRequestMethod("GET");
        con.setConnectTimeout(5000);
        int code=con.getResponseCode();
        if(code==200){
            InputStream ins=con.getInputStream();
            String content=StreamTools.readStream(ins);
            tv.setText(content);
        }
    } catch (Exception e) {
    }
}

}

从editView组件获取网址，然后程序执行到 int code=con.getResponseCode();
这行就不动了，把这行删掉，执行 InputStream ins=con.getInputStream();这行也是没有反应。已经添加了android.permission.INTERNET权限，请问是什么原因

Answer 1

网络请求应该开启一个子线程做网络请求，然后用handle通知主线程更新UI tv.setText(content);