Python矩阵转置问题

Question

将一个5*5的矩阵的最外圈数字逆时针移动一个单位。
原矩阵
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
转置后
2 3 4 5 10
1 7 8 9 15
6 12 13 14 20
11 17 18 19 25
16 21 22 23 24
进一步问个问题，如何将内圈的数字也如最外圈一样转置

Answer 1

先给个外层旋转可适配n*n的,刚才弄成顺时针的了：

import numpy as np
def printLst(lst):
    for row in lst:
        for i in row:
            print(str(i).rjust(3),end=' ')
        print()
    print('='*100)

def turn0(lst,n):
    arr = np.array(lst)
    turnindex = np.array([list(arr[0,:-1]),list(arr[:-1,n-1]),list(arr[n-1,1:][::-1]),list(arr[1:,0][::-1])])
    turnindex = list(np.reshape(turnindex,(1,(n-1)*4))[0])
    newindex = turnindex.copy()
    newindex[-1] = turnindex[0]
    newindex[0:-1] = turnindex[1:]
    lst = list(arr.reshape((1,n**2))[0])
    for i in range(len(lst)):
        t = lst[i]
        if t in turnindex:
            lst[i] = newindex[turnindex.index(t)]
    lst = list(np.array(lst).reshape((n,n)))
    return lst

n = int(input('请输入n:'))
lst = []
for i in range(n):
    row = []
    for j in range(n):
        row.append(n*i+j+1)
    lst.append(row)
printLst(lst)
printLst(turn0(lst,n))