两个字典相加，相同的key保留

Question

dicta = {"a":1,"b":2,"c":3,"d":4,"f":"hello"}
dictb = {"b":3,"d":5,"e":7,"m":9,"k":"world"}
要求写一段代码，实现两个字典的相加，不同的key对应的值保留，相同的key对应的值相加后保留，如果是字符串就拼接，如上示例得到结果为：
dictc = {"a":1,"b":5,"c":3,"d":9,"e":7,"m":9,"f":"hello","k":"world"}

Answer 1

以下这样写，比较简洁：

dicta = {"a":1,"b":2,"c":3,"d":4,"f":"hello"}
dictb = {"b":3,"d":5,"e":7,"m":9,"k":"world"}
dct = dicta.copy()
for k,v in dictb.items():
    dct[k] = dct.get(k,0 if isinstance(v,int) else '')+v
print(dct)