python转c，需要耐心的高瘦

Question

while True:
    try:
        n, m = map(int, input().split())
        l = list()
        for i in range(n):
            l.append(list(map(int, input().split())))
        for x in range(m):
            data = []
            for i in range(n):
                t = []
                for j in range(n):
                    t.insert(0, l[j][i])
                data.append(list(t))
                t.clear()
            l = data
        for i in range(n):
            for j in range(n-1):
                print(l[i][j], end=" ")
            print(l[i][n-1])
    except:
        break

Answer 1

这个循环会不会超时：

#include <stdio.h>
#define N 20
int main()
{
    int n,m,i,j,k,a[N][N];
    while(scanf("%d %d", &n, &m) == 2 && (getchar()) != EOF){
         for(i = 0;i < n; i++){
             for(j = 0;j < n; j++)
                 scanf("%d", &a[i][j]);
         }
         for (k = 0; k < m; k++){
            for (i = 0; i < (n + 1) / 2; i++)
            {
                for (j = 0; j < n / 2; j++) {
                    int temp = a[i][j];
                    a[i][j]  = a[n - 1 - j][i];
                    a[n - 1 - j][i] = a[n - 1 - i][n - 1 - j];
                    a[n - 1 - i][n - 1 - j] = a[j][n - 1 - i];
                    a[j][n - 1 - i] = temp;
                }
            }
         }
         for(i = 0;i < n; i++){
            for(j = 0;j < n; j++)
               printf("%d ",a[i][j]);
            printf("\n");
         }
    }
}