Python3有2个列表，如何完成2个列表的迭代？

Question

列表1：abcdef
列表2：1

#最终结果：a1b, a1c, a1d, a1e

Answer 1

>>> lst1 = list('abcdef')
>>> str1 = '1'
>>> for i in lst1[1:]:
    print(lst1[0]+str1+i)

    
a1b
a1c
a1d
a1e
a1f
>>> for i in lst1[1:]:
    print(lst1[0]+str1+i, end=',')

a1b,a1c,a1d,a1e,a1f,

#改进：最后不出现，号
>>> for i,n in enumerate(lst1[1:]):
    print(lst1[0]+str1+n, end=',' if i+2<len(lst1) else '')

a1b,a1c,a1d,a1e,a1f