问题遇到的现象和发生背景
井字棋的小游戏，我发现有的时候能正常运行判断结果，而有的时候会出现我下完棋后，按两下下enter直接退出显示按任意键继续，这种情况会是什么原因呢?
问题相关代码，请勿粘贴截图
#include<iostream>
using namespace std;
typedef pair<int, int>PII;
char g[100][100];
void init(int n)//初始化棋盘函数
{
for (int i = 2; i <= n + 1; i++)
for (int j = 2; j <= n + 1; j++)
g[i][j] = '*';
}
bool check(int n)//检测棋盘是否占尽
{
for (int i = 2; i <= n+1; i++)
for (int j = 2; j <= n+1; j++)
if (g[i][j] == '*')return false;
return true;
}
void show(int n)//展示棋盘
{
for (int i = 2; i <= n+1; i++)
{
for (int j = 2; j <= n+1; j++)
cout << "|" << g[i][j];
cout << endl;
}
}
bool judge(char a,char b ,int i,int j)//判断字符
{
if (g[i + 1][j] == a && g[i + 2][j] == b)return true;//所在列
else if (g[i + 1][j] == a && g[i - 1][j] == b)return true;
else if (g[i - 1][j] == a && g[i - 2][j] == b)return true;
else if (g[i][j + 1] == a && g[i][j + 2] == b) return true;//所在行
else if (g[i][j + 1] == a && g[i][j - 1] == b)return true;
else if (g[i][j - 1] == a && g[i][j - 2] == b)return true;
else if (g[i - 1][j - 1] == a && g[i + 1][j + 1] == b) return true;//正斜线
else if (g[i - 1][j - 1] == a && g[i - 2][j - 2] == b) return true;
else if (g[i + 1][j + 1] == a && g[i + 2][j + 2] == b)return true;
else if (g[i - 1][j + 1] == a && g[i + 1][j - 1] == b)return true;//反斜线
else if (g[i + 1][j - 1] == a && g[i + 2][j - 2] == b)return true;
else if (g[i - 1][j + 1] == a && g[i - 2][j + 2] == b)return true;
return false;
}
PII chess(char c1,char c2,int n)
{
int w = 0,x,y;
for (int i = 2; i <= n+1; i++)
{
for (int j = 2; j <= n+1; j++)
{
int temp = 0;
if (g[i][j] == '*')
{
if (judge(c2, c2, i, j))temp += 50;
else if (judge(c1, c1, i, j))temp += 25;
else if (judge(c2, '*', i, j))temp += 10;
else if (judge(c1, '*', i, j))temp += 8;
else if (judge('*', '*', i, j))temp += 4;
if (temp > w)
{
w = temp;
x = i; y = j;
}
}
}
}
return { x,y };
}
int main()
{
cout << endl;
cout << "=======欢迎登陆井字棋小游戏======" << endl;
cout << " 祝您游戏愉快!" << endl;
label1:cout << " 1.###开始游戏###.1" << endl;
cout << " 2.###结束游戏###.2" << endl;
for (int i = 0; i <10; i++)
{
for (int j = 0; j <10; j++)g[i][j] = '.';
}
int op1; cin >> op1;
if (op1 == 1)
{
cout << "请选择棋盘边长:(3-5)" << endl;
int x; cin >> x;
init(x);//初始化棋盘
cout << "你选择 X 还是 O" << endl;
cout << "1.X 2.O" << endl;
int op3; cin >> op3;
int pos1 = 0, pos2 = 0;//棋盘坐标
char c1,c2;//c1代表玩家棋子符号,c2代表电脑
if (op3 == 1)
{
c1 = 'X';
c2 = 'O';
}
else
{
c1 = 'O';
c2 = 'X';
}
while (1)
{
cout << "请选择下棋的位置输入坐标" << endl;
cin >> pos1 >> pos2;
g[pos1+1][pos2+1] = c1;//你下了一个位置
//玩家先出,所以玩家可能先赢,所以玩家出完,立马判断
for (int i = 2; i <= x + 1; i++)
{
for (int j = 2; j <= x + 1; j++)
{
if (g[i][j] == c1)
{
if (judge(c1, c1, i, j))
{
cout << "恭喜你,你赢了" << endl;
goto label1;
}
}
}
}
if (check(x))
{
cout << "平局" << endl;
goto label1;
}
PII temp = chess(c1, c2, x);
g[temp.first][temp.second] = c2;//电脑下了一个位置
show(x);
cout << endl;
for (int i = 2; i <= x + 1; i++)
{
for (int j = 2; j <= x + 1; j++)
{
if (g[i][j] == c1)
{
if (judge(c1, c1, i, j))
{
cout << "恭喜你,你赢了" << endl;
goto label1;
}
}
}
}
if (check(x))
{
cout << "平局" << endl;
goto label1;
}
for (int i = 2; i <= x + 1; i++)
{
for (int j = 2; j <= x + 1; j++)
{
if (g[i][j] == c2)
{
if (judge(c2, c2, i, j))
{
cout << "很遗憾,你输了" << endl;
goto label1;
}
}
}
}
}
}
else exit(1);
return 0;
}
运行结果及报错内容
最后一张图在输入后没有继续执行
我的解答思路和尝试过的方法
核心时让电脑学会下棋,主要为judge函数,用来判断对于可以下棋的点也就是'*'的地方,判断周围的符号,每两种符号对应不同的权值
我想要达到的结果
解决输入后强制退出的情况
