For input string报错

Question

时间格式报错

{"success":false,"message":"For input string: \"2022-07-12 16:00:00000\"","data":""}

相关代码

"kssj": "2022-07-12T16:00:00.745Z", 
"jssj": "2022-07-13T16:00:00.745Z",

SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
JsrcuJmsVo jsrcuJmsVo=new JsrcuJmsVo();
String kssj1 = (String) rowData.get("kssj");
String kssj = kssj1.replace("T", " ").substring(0, 19);//2022-07-12 16:00:00
String jssj1 = (String) rowData.get("jssj");
String jssj = jssj1.replace("T", " ").substring(0, 19);
jsrcuJmsVo.setDateStart(kssj);
jsrcuJmsVo.setDateExpired(jssj);
String param = JSONUtils.toJSON(jsrcuJmsVo);
log.info(">>>JSON，参数：{}",param);        
HttpUtils.HttpServiceResponse response = null;
Map<String,String> headers = new HashMap<>();
headers.put("Content-Type", "application/json");
headers.put("Connection", "keep-alive");
response = HttpUtils.post(url, headers, param);
log.info(">>>调用接口返回，结果：{}", response.getResponseText());

运行结果及报错内容

param：运行结果

"dateStart":"2022-07-12 16:00:00","dateExpired":"2022-07-13 16:00:00"

response.getResponseText()：报错
(boolean) JSONUtils.fromJSON(response.getResponseText(), JSONObject.class).get("success")报错：

{"success":false,"message":"For input string: \"2022-07-12 16:00:00000\"","data":""}

我的解答思路

For input string：百度说是因为整型问题，问题是我的都是String类型，没有整型。为什么还是有这个报错。

结果

怎么解决这个问题？谢谢

Answer 1

看这个好像不是字符，像日期类型，你可以改成日期试试