c语言:为什么输入一个数字后报错

Question

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
int main()
{
int i;
scanf("%d",&i);
charp;
p=(char)malloc(i);
strcpy(p,"malloc success");
puts(p);
rerurn 0;
}

Answer 1

p的定义错了
应该是：
char* p;
p = (char*)malloc(i);