两个值相比,判断他们是否为倍数,如果不是倍数的话,就取余数

Question

问题遇到的现象和发生背景

两个值相比,判断他们是否为倍数,如果不是倍数的话,就取余数

相当于:
a = 11;
b = 2;
a和b相比,取出一个1的值

问题相关代码，请勿粘贴截图

        //如果是整数
        if (supplierCodeSum % valueOf == 0) {
            num = supplierCodeSum / valueOf;
            for (long i = 0; i < num; i++) {
                HyBarCodeTem saveItem = HyBarCodeTem.builder().build();
                saveItem.setTemBachTime(hyBarCodeTem.getTemBachTime());
                saveItem.setCustomerMaterialCode(hyBarCodeTem.getCustomerMaterialCode());
                saveItem.setCreateTime(DateUtils.getNowDate());
                saveItem.setCreateBy(SecurityUtils.getLoginUser().getUsername());
                saveItem.setCustomerMaterialCodeNo(materialSku);
//            int i1 = hyBarCodeTemMapper.insertHyBarCodeTem(hyBarCodeTem);
                batchList.add(saveItem);
            }
        } else {
            //如果有零头
            num = supplierCodeSum / valueOf + 1;
            for (long i = 0; i < num; i++) {
                HyBarCodeTem saveItem = HyBarCodeTem.builder().build();
                saveItem.setTemBachTime(hyBarCodeTem.getTemBachTime());
                saveItem.setCustomerMaterialCode(hyBarCodeTem.getCustomerMaterialCode());
                saveItem.setCreateTime(DateUtils.getNowDate());
                saveItem.setCreateBy(SecurityUtils.getLoginUser().getUsername());
                if(i == num-1){
                    //如何取余数,还请指点一下,谢谢
                }else{
                    saveItem.setCustomerMaterialCodeNo(materialSku);
                }

//            int i1 = hyBarCodeTemMapper.insertHyBarCodeTem(hyBarCodeTem);
                batchList.add(saveItem);
            }
        }

Answer 1

else里num = supplierCodeSum / valueOf + 1;换成 num = supplierCodeSum % valueOf ;