douliedai4838 2013-09-11 03:28
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使用PHP中的整数过滤数组值

I am trying to filter a php array by comparing a field containing a unix date string ("start-unix-date") with the current unix time (simplified in this example as "15"). I want to keep only items where the unix date is in the future (>= than present).

Here is a simplified version of my code - based on this filtering method:

$my_array = array(
    array( 'start-date-unix' => '20' ), 
    array( 'start-date-unix'  => '10')
);

$unix_now = 15;

function filter_future($var) {
    return (is_array($var) && $var['start-date-unix'] >= $unix_now)
}

$filtered_array = array_filter($my_array, "filter_future");

var_dump($filtered_array);

The expected result:

The $filtered_array should keep only the item with a "start-date-unix" value of 20.

Actual result:

That filter doesn't do anything, every value is accepted. The $filtered_array still contains both items.

What works:

In the filter_future, if I enter the number (15) instead of the $unix_now variable, it works as expected: only the "20" item is kept.

So I suspect that there's an issue with $unix_now being a string vs an integer. I tried many methods of enforcing it being an integer but nothing seems to work :(

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  • douzhuiqiu4923 2013-09-11 03:32
    关注

    $unix_now should be a global variable inside filter_future-function.

    $unix_now = 15;
    
    function filter_future($var) {
        global $unix_now;
        return (is_array($var) && (int) $var['start-date-unix'] >= $unix_now)
    }
    
    $filtered_array = array_filter($my_array, "filter_future");
    
    var_dump($filtered_array);
    

    The result:

    array(1) { [0]=> array(1) { ["start-date-unix"]=> string(2) "20" } } 
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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