python中单例模式和初始化函数带参数冲突吗？

Question

 请教一个问题python中单例模式和初始化函数带参数冲突吗？

import time


class po_more:
    def __new__(cls, *args, **kwargs):
        if not hasattr(cls, '_a'):
            cls._a = super().__new__(cls, *args, **kwargs)
            print('11111111111')
        return cls._a


    def __init__(self,t) -> None:
        print('111111',t)

    def add(self, num):
        n = 0
        if n < num:
            n += 1
            time.sleep(1)
            print(n)


if __name__ == '__main__':
    a = po_more('1')
    b = po_more('1')
    a.add(8)
    b.add(5)

上面的代码中原来是没有参数t的，当我增加参数t之后(相应的实参‘1’也删除)，执行就报错，删除后就不报错，想知道为什么？
执行报错信息：

Traceback (most recent call last):
  File "f:\mywscode\py2\po.py", line 24, in <module>
    a = po_more('1')
  File "f:\mywscode\py2\po.py", line 7, in __new__  
    cls._a = super().__new__(cls, *args, **kwargs)  
TypeError: object.__new__() takes exactly one argument (the type to instantiate)

想要正常的添加参数，要怎么操作？请不吝赐教！

Answer 1

所有类默认继承object，所以super()会调用object的__new__方法，而object类只能接收一个。
cls._a = super().__new__(cls, *args, **kwargs)
改成
cls._a = super().__new__(cls)
就可以了