dongwei9771 2010-12-04 09:53
浏览 28

阅读网址内容,无缓冲的PHP

This function reads an url

 function get_url_contents($url){
    $crl = curl_init();
    $timeout = 5;
    curl_setopt ($crl, CURLOPT_URL,$url);
    curl_setopt ($crl, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt ($crl, CURLOPT_CONNECTTIMEOUT, $timeout);
    $ret = curl_exec($crl);
    curl_close($crl);
    return $ret;
}

but I want to read it unbuffered, so I can read an unbuffered cgi-script, e.g., to analyze it while it is loading? How do I do this in php?

  • 写回答

1条回答 默认 最新

  • doulu4976 2010-12-05 06:29
    关注

    You could use fsockopen(), such as in the first example given here: http://www.php.net/manual/en/function.fsockopen.php

    评论

报告相同问题?

悬赏问题

  • ¥15 在获取boss直聘的聊天的时候只能获取到前40条聊天数据
  • ¥20 关于URL获取的参数,无法执行二选一查询
  • ¥15 液位控制,当液位超过高限时常开触点59闭合,直到液位低于低限时,断开
  • ¥15 marlin编译错误,如何解决?
  • ¥15 有偿四位数,节约算法和扫描算法
  • ¥15 VUE项目怎么运行,系统打不开
  • ¥50 pointpillars等目标检测算法怎么融合注意力机制
  • ¥20 Vs code Mac系统 PHP Debug调试环境配置
  • ¥60 大一项目课,微信小程序
  • ¥15 求视频摘要youtube和ovp数据集