var list = ["a", "b", "c", "d", ] , routers = [];
var asyncRoutes = [
{ name: "a",
children: [
{ name: "b", }, { name: "c", }, { name: "d",}, { name: "e", },{ name: "f", },
],
},
];
如何遍历出来
asyncRoutes = [ { name: "a",children: [ { name: "b", }, { name: "c", }, { name: "d",} ], },] 这样的格式呢?
我是这样的写法,不能得到 children里面的数据
list.forEach((key) => {
routers.push(
...asyncRoutes.filter((item) => {
if (item.children && item.children.length > 1) {
item.children = item.children.filter((i) => {
return i.name == key;
});
}
return item.name === key;
})
);
});
2条回答 默认 最新
- 黎明不管黑夜的星空 2022-08-15 02:28关注
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <meta name="viewport" content="width=device-width, initial-scale=1.0"> <title>Document</title> </head> <body> <script> var list = ["a", "b", "c", "d",], routers = []; var asyncRoutes = [ { name: "a", children: [ { name: "b", }, { name: "c", }, { name: "d", }, { name: "e", }, { name: "f", }, ], }, ]; var obj = {}; obj.children = []; var data = list.forEach((item, index) => { if (index == 0) { obj.name = item; return } var child_obj = { children: item } obj.children.push(child_obj); }); routers.push(obj) console.log(routers); </script> </body> </html>
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