python通过矩阵操作得到想要的结果

Question

[5 4 3 2 1
5 4 3 1 2
5 4 2 3 1
5 4 1 3 2
5 4 2 1 3
5 4 1 2 3
5 3 4 2 1
5 3 4 1 2
5 2 4 3 1
5 1 4 3 2
5 2 4 1 3
5 1 4 2 3]
上述矩阵是否存在一个矩阵操作算法得到以下结果
每一行出现相邻的目标数字，即在该数组中记为0，反之记为1，首尾也算相邻，例如
S1_2=[0,0,1,1,0,0,0,0,1,1,1,1]
S1_3=[1,0,0,0,0,1,1,1,0,1,0,1]
S1_4=[1,1,1,0,1,0,1,0,1,0,0,0]
S1_5=[0,1,0,1,1,1,0,1,0,0,1,0]
S2_3=[0,1,0,0,1,0,1,1,1,0,1,0]
S2_4=[1,1,0,1,0,1,0,1,0,1,0,0]
S2_5=[1,0,1,0,1,1,1,0,0,0,0,1]
S3_4=[0,0,1,1,1,1,0,0,0,0,1,1]
S3_5=[1,1,1,1,0,0,0,0,1,1,0,0]
S4_5=[0,0,0,0,0,0,1,1,1,1,1,1]
共10个数组

Answer 1

我用矩阵乱算算出来了，结题了