C语言结构体指针形参与实参不符

Question

C语言：形参和实参不符

#include<stdio.h>

#include<string.h>
struct contact {
char phone[20];
char email[20];
};

struct person_plus {
char name[20];
char gender[20];
double height;
double weight;

};

void change(struct person_plus* per)
{
strcpy((*per).name, "David");
//per->name = "David";
strcpy((*per).gender, "man");
//per->gender = "man";
(*per).height = 176;
(*per).weight = 118;

//(*per).a.email = "None";

}
int main()
{

struct person_plus {
    char name[20];
    char gender[20];
    double height;
    double weight;

};

struct person_plus Uimmy = { "Uimmy","man",170,100};
change(&Uimmy);

}

![img](https://img-mid.csdnimg.cn/release/static/image/mid/ask/61264281906616.png "#lef

Answer 1

有注释说明，仅供参考！ 谢谢！

#include<stdio.h>
//#include
struct contact
{
    char phone[20];
    char email[20];
};


struct person_plus
{
    char name[20];
    char gender[20];
    double height;
    double weight;

};


void change(struct person_plus *per)
{
    strcpy((*per).name, "David");
    // per->name = "David";
    strcpy((*per).gender, "man");
    // per->gender = "man";
    (*per).height = 176;
    (*per).weight = 118;

    // (*per).a.email = "None";
}

int main()
{
    #if 0
    这里的结构体不用定义了，因为change函数访问不到局部变量
    它只能访问前面定义的那个全局结构体变量
    而你在这里定义的Uimmy变量只是局部变量，跑出去别的函数都不认识了。
    
    struct person_plus
    {
        char name[20];
        char gender[20];
        double height;
        double weight;

    };
    #endif

    struct person_plus Uimmy = { "Uimmy", "man", 170, 100 };
    change(&Uimmy);
    
    printf("%s,%s,%.0lf,%.0lf\n",Uimmy.name,Uimmy.gender,Uimmy.height,Uimmy.weight);
    
    puts("ok");
    return 0;
}