python对大括号里面的大括号的数据排序后按顺序导出大括号后面的name怎么操作呢

Question

代码如下

根据left的从小到大进行排序，然后导出name。并把name变成对应的英文
即最后结果print（"right","right","up","left"）

Answer 1

dict_1 = {
    "log_id": 1,
    "results": [
        {
            "location": {
                "height": 29,
                "left": 360,
                "top": 76,
                "width": 32
            },
            "name": "上",
            "score": 0.98
        },
        {
            "location": {
                "height": 26,
                "left": 471,
                "top": 68,
                "width": 27
            },
            "name": "左",
            "score": 0.92
        },
        {
            "location": {
                "height": 28,
                "left": 268,
                "top": 79,
                "width": 30
            },
            "name": "右",
            "score": 0.89
        },
        {
            "location": {
                "height": 31,
                "left": 200,
                "top": 73,
                "width": 29
            },
            "name": "右",
            "score": 0.88
        }
    ]
}


def translate(word):
    dict_word = {'right': '右', 'left': '左', 'top': '上'}
    # 获取value的key
    name = list(dict_word.keys())[list(dict_word.values()).index(word)]
    return name


list_1 = dict_1['results']
list_len = len(list_1)
# 冒泡排序
for i in range(list_len):
    for j in range(0, list_len - i - 1):
        # 比较location中的left的值
        if list_1[j]['location']['left'] > list_1[j + 1]['location']['left']:
            # 交换值
            list_1[j], list_1[j + 1] = list_1[j + 1], list_1[j]
print(list_1)
# [{'location': {'height': 31, 'left': 200, 'top': 73, 'width': 29}, 'name': '右', 'score': 0.88}, {'location': {
# 'height': 28, 'left': 268, 'top': 79, 'width': 30}, 'name': '右', 'score': 0.89}, {'location': {'height': 29, 
# 'left': 360, 'top': 76, 'width': 32}, 'name': '上', 'score': 0.98}, {'location': {'height': 26, 'left': 471, 
# 'top': 68, 'width': 27}, 'name': '左', 'score': 0.92}] 
for i in range(list_len):
    print(translate(list_1[i]['name']), end=' ')
# right right top left 

这么写怎么样？