二维数组中字符串指针打印问题

Question

二维数组指针问题

##include<stdio.h>

int main()
{

int a[3][1] = {
    {1},{2},{1}
};

int(*pa)[1] = a;
printf("%d\n", pa);

char c[3][1] = {
{'A'},{'S'},{'A'}
};
char(*pc)[1] = c;
printf("%d\n", pc);


char b[3][10] = {
    {"AAA"},{"SAAAA"},{"RSS"}
};
char(*pb)[10] = b;
printf("%s\n", pb);
printf("%s\n", pb+1);
printf("%s\n", pb + 2);
printf("%d\n", pb);
printf("%d\n", *(pb)+1);
printf("%d\n", pb + 1);
printf("%d\n", pb + 2);

printf("%s\n", *(pb)+10);
printf("%s\n", *(pb)+11);
printf("%s\n", *(pb)+12);

printf("%s\n", *(pb)+20);


printf("%c\n", **(pb));
printf("%c\n", *(*(pb)+1));
printf("%c\n", *(*(pb)+2));
printf("%c\n", *(*(pb)+10));
printf("%c\n", *(*(pb)+11));
printf("%c\n", *(*(pb)+12));
printf("%c\n", *(*(pb)+13));
printf("%c\n", *(*(pb)+14));
printf("%c\n", *(*(pb)+20));

}

根据代码 printf("%d\n", pb); printf("%d\n", pb + 1);

printf("%d\n", pb + 2); 我猜此处 pb 仍为地址，但是printf("%s\n", pb);打出来的是内容，是否说明printf("%s\n", pb);可直接根据首地址打出内容，因为我试了下printf("%c\n", (pb));是不可以的，想要打出指针的内容还是需要printf("%c\n", **(pb));

Answer 1

你的想法是对的，字符型指针可以输出字符串的内容，指针自动的向后移动，直到遇到\0则停止。你可以试试

char *str = "HelloWorld";
printf("%s",str);

同样可以达到输出整个字符串的效果