douqilai4263
2014-04-02 19:26
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用ajax调用php并返回多个变量?

I am trying to use javascript to call a php script which then will return multiple variables back to my javascript so I can manipulate them.

This is my JS.

                $.ajax({ 
                    url: 'test.php',
                    data: { id : lastFileId },
                    success: function(output) {
                        alert(output);
                    }
                });

my PHP

<?php
    $fileId = ($_GET['id']);
    $num1 = 1;
    $num2 = 2;

?>

From here, how can I return variables $num1 and $num2 so i can use them in my javascript. Is it possible?

also this is a very basic idea of what I have planned to do if I can achieve this.

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我正在尝试使用javascript调用php脚本,然后将多个变量返回给我的javascript,这样我就可以了 这是我的JS。

  $ .ajax({
 url:'test.php',
  data:{id:lastFileId},
 success:function(output){
 alert(output); 
} 
}); 
   
 
 

my PHP

 &lt;?php 
 $ fileId =($ _GET ['id']); 
 $ num1 = 1; 
 $ num2 = 2; 
  
?&gt; 
   
 
 

从这里,如何返回变量$ num1和$ num2,以便我可以在我的javascript中使用它们。 是否可能?

如果我能做到这一点,这也是我计划做的一个非常基本的想法。

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5条回答 默认 最新

  • dongmu5596 2014-04-02 19:31
    最佳回答

    You can return as many variables as you want with json_encode().

    Try in your PHP:

    <?php
    echo json_encode(array($num1, $num2));
    ?>
    

    You can add to that array , $num3, $num4, ... and so on.

    In your JS, you can access each number as follows.

    First, you will need this line of code to parse the encoded JSON string, in your success function.

    var result = $.parseJSON(output);

    That sets result as a JSON object. Now you can access all fields within result:

    • result[0] -- $num1 in PHP
    • result[1] -- $num2 in PHP
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