在FOR循环下运行， time.localtime运行终止

Question

问题遇到的现象和发生背景

在FOR循环下运行，第一次循环运行正常，第二次循环time_local = time.localtime(time1)终止

问题相关代码，请勿粘贴截图

        time1 = jobs['time']
        print('time1',time1)
        time_local = time.localtime(time1)
        print('time_local',time_local)
        # time2 = str(time1)
        # 转换成新的时间格式(精确到秒)
        time3 = time.strftime("%Y-%m-%d %H:%M:%S", time_local)
        print(time3)  # 2021-11-09 09:46:48
        #print('time2',time2)
        time = []
        time.append(time3)
        print('time',time)

运行结果及报错内容

time1 1640109638
time_local time.struct_time(tm_year=2021, tm_mon=12, tm_mday=22, tm_hour=2, tm_min=0, tm_sec=38, tm_wday=2, tm_yday=356, tm_isdst=0)
2021-12-22 02:00:38
time ['2021-12-22 02:00:38']
time1 1640035455
Process finished with exit code 0

我想要达到的结果

在FOR循环下，一直运行

Answer 1

看代码没问题，把全部代码贴出来看下，或者你重新运行一下看下呢