用的是VS2019，自己写的函数swap，函数swap没有改变实参的值是为什么，求解答.

Question

#define _CRT_SECURE_NO_WARNINGS 1
#include<stdio.h>

void swap(int x, int y)
{
    int temp;
    temp = x;
    x = y;
    y = temp;
}
int main()
{
    int a = 0;
    int b = 0;
    int c = 0;
    scanf("%d%d%d", &a, &b, &c);
    if (a > b)
        swap(a, b);
    if (a > c)
        swap(a, c);
    if (b > c)
        swap(b, c);
    printf("%d/%d", a, c);
    return 0;
}

Answer 1

#define _CRT_SECURE_NO_WARNINGS 1
#include<stdio.h>
#include <iostream>
//在前面用&，可以实现传参赋值！
void swap(int &x, int &y)
{
    int temp;
    temp = x;
    x = y;
    y = temp;
}
int main()
{
    int a;
    int b;
    int c;
    scanf("%d%d%d", &a, &b, &c);
    if (a > b)
        swap(a, b);
    if (a > c)
        swap(a, c);
    if (b > c)
        swap(b, c);
    printf("%d/%d", a, c);
    system("pause");
    return 0;
}

结果：