使arr1与arr中，id重复的arr1替换arr，然后arr1多余的对象id清空结合得到一个新数组

Question

使arr1与arr中，id重复的arr1替换arr，然后arr1多余的对象id清空结合得到一个新数组

arr = [
    {
        id: "1",
        name: "1"
    },
    {
        id: "2",
        name: "2"
    },
    {
        id: "3",
        name: "3"
    }
]

arr1 = [
    {
        id: "1",
        name: "3"
    },
    {
        id: "4",
        name: "4"
    },
    {
        id: "5",
        name: "5"
    }
]
//使arr1与arr中，id重复的arr1替换arr，然后arr1多余的对象id清空得到的结果大概是这样的，
temp = [
    {
        id: "1",
        name: "3"
    },
    {
        id: "",
        name: "4"
    },
    {
        id: "",
        name: "5"
    }
]

Answer 1

      arr1.map((item) => {
        arr.some((item2) => item2.id == item.id) ? item.id : (item.id = '');
      });
      console.log(arr1);